在Android中使用scala编程(二)

 Scala中使用HTTP访问地址可以使用以下简便方式

1.声明对象

 

abstract class OptionalParam  case class Id(id : String) extends OptionalParam  case class UserId(user_id : Long) extends OptionalParam  case class ScreenName(screen_name : String) extends OptionalParam  case class Since(since_id : Long) extends OptionalParam  case class Max(max_id : Long) extends OptionalParam  case class Count(count : Int) extends OptionalParam  case class Page(page : Int) extends OptionalParam  case class InReplyToStatusId(status_id : Long) extends OptionalParam

2.传递请求

def userTimeline(options : OptionalParam*) : List[Status] =    {      val url = "http://twitter.com/statuses/user_timeline"      var urlId = ".xml"      val optionsStr = new StringBuffer("?")      for (option <- options)      {        option match        {          case Id(id) =>            urlId = "/" + id.toString() + ".xml"          case UserId(user_id) =>            optionsStr.append("user_id=" + user_id.toString() + "&")          case Since(since_id) =>            optionsStr.append("since_id=" + since_id.toString() + "&")          case Max(max_id) =>            optionsStr.append("max_id=" + max_id.toString() + "&")          case Count(count) =>            optionsStr.append("count=" + count.toString() + "&")          case Page(page) =>            optionsStr.append("page=" + page.toString() + "&")        }      }            val (statusCode, statusBody) =        Scitter.execute(url + urlId + optionsStr.toString(), username, password)}

这样话，可以简单统一化参数请求。