joj1817

1817: Triangle

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ResultTIME LimitMEMORY LimitRun TimesAC TimesJUDGE5s8192K2665747Standard

2^nd JOJ Cup Online VContest Problem

Given three integers a, b and c(|a|, |b|, |c|<10000), determine if they can compose a valid triangle. If so, further determine which kind of the triangle it is.

Input Specification

The input consists of several lines, each of which contains three integers a, b and c.

Output Specification

For each group of a b and c, first print "Case K:", a space, and then one of the following four lines:

is not a valid triangle.
is a sharp triangle.
is a right triangle.
is a blunt triangle.

corresponding to your determinant, where K is the number of the test cases starting from 1.

Sample Input

3 4 5
3 3 3
1 2 3
3 4 6

Sample Output

Case 1: is a right triangle.
Case 2: is a sharp triangle.
Case 3: is not a valid triangle.
Case 4: is a blunt triangle.

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This problem is used for contest: 104  167  181  185 

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Problem Set with Online Judge System Version 3.12
Jilin University

Developed by skywind, SIYEE

 

 

 

 

#include<cstdio>
int u,v,m;
bool istriangle(int i,int j,int s)
{
    if(i+j>s&&i+s>j&&j+s>i)return true;
    return false;
}
bool isrighttriangle()//直角
{
    if(u==v+m||v==u+m||m==u+v)return true;
    return false;
}
bool issharptriangle()//锐角
{
    if(u+v>m&&u+m>v&&v+m>u)return true;
    return false;
}
bool isblunttriangle()//钝角
{
    if(u>v+m||v>u+m||m>u+v)return true;
    return false;
}
int main()
{
    int n=0;
    int i,j,s;
    while(scanf("%d%d%d",&i,&j,&s)==3)
    {
        n++;
       
        u=i*i;v=j*j; m=s*s;
        if(!istriangle(i,j,s))
        printf("Case %d: is not a valid triangle.\n",n);
        else if(isrighttriangle())
        printf("Case %d: is a right triangle.\n",n);
        else if(issharptriangle())
        printf("Case %d: is a sharp triangle.\n",n);
        else
        printf("Case %d: is a blunt triangle.\n",n);

    }
    return 0;
}