POJ 2602 Superlong sums 大整数求和

题意：大整数相加。

#include <cstdio>int array[1000002];int main(){__int64 n, i;char a, b;int carry = 0;scanf( "%I64d", &n ); getchar();for ( i = 0; i < n; i++ ){a = getchar();getchar();                b = getchar();getchar();array[i] = a - '0' + b - '0';}for ( i = n - 1; i > 0; i-- ){if ( array[i] >= 10  ){array[i] -= 10;array[i-1]++;}}for ( i = 0; i < n; i++ )putchar( array[i] + '0' ); putchar('\n');return 0;}