UESTC 1425 Another LCIS
来源:互联网 发布:大数据上市公司排名 编辑:程序博客网 时间:2024/05/15 12:10
继续种树哈~~
类似之前做的hdu的LCIS,不过这个操作是,某个区间加上一个值。
基本操作和之前那个LCIS差不多,只不多我LCIS结点里没存左右端点的值,直接映射到数组了,但是这个不存的话会很麻烦。。
所以纠结了一会,后来把端点信息存到结点里,改变的时候向上更新就没问题啦。
比LCIS增加了结点信息,这个区间整体加上的值,以及这个区间的左右的端点值。
#include <set>#include <map>#include <queue>#include <stack>#include <math.h>#include <stdio.h>#include <stdlib.h>#include <iostream>#include <limits.h>#include <string.h>#include <string>#include <algorithm>#define MID(x,y) ( ( x + y ) >> 1 )#define L(x) ( x << 1 )#define R(x) ( x << 1 | 1 )#define FOR(i,s,t) for(int i=(s); i<(t); i++)#define BUG puts("here!!!")#define STOP system("pause")#define file_r(x) freopen(x, "r", stdin)#define file_w(x) freopen(x, "w", stdout)using namespace std;const int MAX = 100010;int a[MAX];struct Tnode{// 一维线段树 int l,r,lval, rval, max, add, ll, rr; int len() { return r - l;} int mid() { return MID(l,r);} bool in(int ll,int rr) { return l >= ll && r <= rr; } void lr(int ll,int rr){ l = ll; r = rr;}};Tnode node[MAX<<2];void Updata_val(int t) {node[t].ll = node[L(t)].ll;node[t].rr = node[R(t)].rr; node[t].lval = node[L(t)].lval; if( node[L(t)].lval == node[L(t)].len() && node[R(t)].ll > node[L(t)].rr ) node[t].lval += node[R(t)].lval; node[t].rval = node[R(t)].rval; if( node[R(t)].rval == node[R(t)].len() && node[R(t)].ll > node[L(t)].rr ) node[t].rval += node[L(t)].rval; int mval = 0; if( node[R(t)].ll > node[L(t)].rr ) mval = node[L(t)].rval + node[R(t)].lval; node[t].max = max(mval, max(node[L(t)].max, node[R(t)].max)); node[t].max = max(node[t].max, max(node[t].lval, node[t].rval)); } void Build(int t,int l,int r){node[t].add = node[t].lval = node[t].rval = node[t].max = 0;node[t].lr(l,r);if( node[t].len() == 1 ){node[t].lval = node[t].rval = node[t].max = 1;node[t].ll = node[t].rr = a[node[t].l];return ;}int mid = MID(l,r);Build(L(t),l,mid);Build(R(t),mid,r);Updata_val(t);}void Updata_llrr(int t, int add){node[t].ll += add;node[t].rr += add;}void Push_down(int t){if( node[t].len() == 1 ){node[t].add = 0;return ;}if( node[t].add ){node[L(t)].add += node[t].add;Updata_llrr( L(t), node[t].add );node[R(t)].add += node[t].add;Updata_llrr( R(t), node[t].add);node[t].add = 0;}}void Updata(int t,int l,int r,int val){if( node[t].in(l,r) ){node[t].add += val;Updata_llrr(t, val);Push_down(t);return ;}if( node[t].len() == 1 ) return ;Push_down(t);int mid = node[t].mid();if( l < mid ) Updata(L(t),l,r,val);if( r > mid ) Updata(R(t),l,r,val);Updata_val(t);}int Query(int t,int l,int r) { if( node[t].in(l,r) ) return node[t].max; if( node[t].len() == 1 ) return 0; Push_down(t); int mid = node[t].mid(); int ans = 0; if( r <= mid ) ans = max(ans, Query(L(t),l,r)); else if( l >= mid ) ans = max(ans, Query(R(t),l,r)); else { ans = max(ans, Query(L(t),l,r)); ans = max(ans, Query(R(t),l,r)); int ll, rr; if( node[L(t)].r - node[L(t)].rval > l ) ll = node[L(t)].rval; else ll = node[L(t)].r - l; if( node[R(t)].l + node[R(t)].lval > r ) rr = r - node[R(t)].l; else rr = node[R(t)].lval; ans = max(ans, ll); ans = max(ans, rr); if( node[R(t)].ll > node[L(t)].rr ) { int mval = rr + ll; ans = max(ans, mval); } } Updata_val(t); return ans; } int main(){int ncases, n, m, x, y, val, ind = 1;char op[5];scanf("%d", &ncases);while( ncases-- ){scanf("%d%d", &n, &m);FOR(i, 0, n)scanf("%d", &a[i]);Build(1, 0, n);printf("Case #%d:\n", ind++);while( m-- ){scanf("%s", op);if( op[0] == 'a' ){scanf("%d%d%d", &x, &y, &val);Updata(1, x-1, y, val);}else{scanf("%d%d", &x, &y);int ans = Query(1, x-1, y);printf("%d\n", ans);}}}return 0;}
- UESTC 1425 Another LCIS
- UESTC 1425 Another LCIS
- UESTC - 1425 Another LCIS
- UESTC 1425 Another LCIS
- uestc 1425——Another LCIS
- UESTC 360(1425) another LCIS
- 【37.07%】【UESTC 360】Another LCIS
- uestc 1425 Another LCIS(线段树 最长递增序列)
- uestc 1425 Another LCIS(成段更新)
- uestc Another LCIS 区间线段树
- UESTC 360 Another LCIS 线段树
- UESTC 360 Another LCIS (线段树 维护LCIS)
- [UESTC]Another LCIS[线段树][区间合并][成段修改]
- uestc Another LCIS(区间更新,区间合并)
- UESTC 360 Another LCIS(线段树区间更新)
- UESTC 360 Another LCIS(线段树 x 经典区间合并姿势)
- 【线段树】Another LCIS
- UESTC1425 Another LCIS
- 树视列表和树控列表【转】
- 连接数据库中的两张表
- 成为一名好的程序员
- 乔布斯一生都在模仿的偶像:两度从哈佛大学退学的发明家Edwin H. Land
- Ubuntu下配置qooxdoo
- UESTC 1425 Another LCIS
- 杭电acm 1004 (Let the Balloon Rise)
- 笔记本外接显示器无法调至最佳分辨率的问题
- WinEdt中添加和删除块注释的快捷键
- 华尔街日报:乔布斯葬礼已经于周五进行
- POJ 1523
- Oracle 更新 OPatch 工具版本 的方法 说明
- as中Astar自动寻路算法
- 《纽约时报》:乔布斯是伟大的暴君