SOJ-2511(两次用栈,一次从前往后一次从后往前)
来源:互联网 发布:mysql 停止主从同步 编辑:程序博客网 时间:2024/06/04 18:03
/****************************************************************************************************** ** Copyright (C) 2011.06.12(8:000)-2013.07.01 ** Author: famousDT <13730828587@163.com> ** Edit date: 2011-06-12******************************************************************************************************/#include <stdio.h>#include <stdlib.h>//abs,atof(string to float),atoi,atol,atoll#include <math.h>//atan,acos,asin,atan2(a,b)(a/b atan),ceil,floor,cos,exp(x)(e^x),fabs,log(for E),log10#include <vector>#include <queue>#include <map>#include <set>#include <stack>#include <string>#include <iostream>#include <string.h>//memcpy(to,from,count#include <ctype.h>//character process:isalpha,isdigit,islower,tolower,isblank,iscntrl,isprll#include <algorithm>using namespace std;//typedef long long ll;#define PI acos(-1)#define MAX(a, b) ((a) > (b) ? (a) : (b))#define MIN(a, b) ((a) < (b) ? (a) : (b))#define MALLOC(n, type) ((type *)malloc((n) * sizeof(type)))#define FABS(a) ((a) >= 0 ? (a) : (-(a)))struct my{ int a; int b;}wo[50005];int main(){ int n; int i; int d[50005][2]; while (scanf("%d", &n) == 1) { int t[50005] = {0}; t[0] = 0; for (i = 0; i < n; ++i) scanf("%d%d", &wo[i].a, &wo[i].b); stack<my> s; s.push(wo[0]); for (i = 1; i < n; ++i) { while (!s.empty() && wo[i].a > s.top().a) { t[i] += s.top().b; s.pop(); } s.push(wo[i]); } while (!s.empty()) s.pop(); s.push(wo[n - 1]); for (i = n - 2; i >= 0; --i) { while (!s.empty() && wo[i].a > s.top().a) { t[i] += s.top().b; s.pop(); } s.push(wo[i]); } int max = -1; for (i = 0; i < n; ++i) if (max < t[i]) max = t[i]; printf("%d\n", max); } return 0;}