android基础--使用Pull解析器生成XML文件

 

解析person.xml文件：

person.xml

<?xml version="1.0" encoding="UTF-8"?><persons><person id="23"><name>张三</name><age>3</age></person><person id="20"><name>Mary</name><age>25</age></person></persons>

1.Manifest.xml中增加

<uses-library android:name="android.test.runner" /><instrumentation android:name="android.test.InstrumentationTestRunner"              android:targetPackage="cn.com.xml" android:label="Tests for My App" />

建立person.xml对应的javabean类

public class Person {private String name;private int id;private int age;public String getName() {return name;}public void setName(String name) {this.name = name;}public int getId() {return id;}public void setId(int id) {this.id = id;}public int getAge() {return age;}public void setAge(int age) {this.age = age;}@Overridepublic String toString() {return "Person [age=" + age + ", id=" + id + ", name=" + name + "]";}}

2.业务层中解析person.xml

public static ArrayList<Person> getPersons(InputStream xml)throws Exception {ArrayList<Person> persons = null;Person person = null;XmlPullParser parser = Xml.newPullParser();parser.setInput(xml, "utf-8");int event = parser.getEventType();while (event != XmlPullParser.END_DOCUMENT) {switch (event) {case XmlPullParser.START_DOCUMENT:persons = new ArrayList<Person>();break;case XmlPullParser.START_TAG:if ("person".equals(parser.getName())) {person = new Person();person.setId(Integer.parseInt(parser.getAttributeValue(0)));} else if ("name".equals(parser.getName())) {person.setName(parser.nextText());} else if ("age".equals(parser.getName())) {person.setAge(Integer.parseInt(parser.nextText()));}break;case XmlPullParser.END_TAG:if ("person".equals(parser.getName())) {persons.add(person);person = null;}default:break;}event = parser.next();}return persons;}

3.测试

public void testGetPersons() throws Throwable{InputStream xml = this.getClass().getClassLoader().getResourceAsStream("person.xml");ArrayList<Person> al = PullXml.getPersons(xml);for(Person person: al){Log.i("PersonTest", person.toString());}}

集合xml的转换，将例子中类路径下的person.xml文件读取并存放到手机中应用程序的/data/data/应用程序包/files下

1.业务层方法：

public static void savePersons(ArrayList<Person> persons, OutputStream out)throws Exception{XmlSerializer xs = Xml.newSerializer();xs.setOutput(out, "utf-8");xs.startDocument("utf-8", true);xs.startTag(null, "persons");for(Person p : persons){xs.startTag(null, "person");xs.attribute(null, "id", p.getId()+"");xs.startTag(null, "name");xs.text(p.getName());xs.endTag(null, "name");xs.startTag(null, "age");xs.text(p.getAge()+"");xs.endTag(null, "age");xs.endTag(null, "person");}xs.endTag(null, "persons");xs.endDocument();out.flush();out.close();}

2.测试

public void testSavePersons() throws Throwable{InputStream xml = this.getClass().getClassLoader().getResourceAsStream("person.xml");ArrayList<Person> al = PullXml.getPersons(xml);FileOutputStream out = new FileOutputStream(new File(getContext().getFilesDir(),"zzzz.xml"));PullXml.savePersons(al, out);}