用广度优先搜索解迷宫问题 By LYLtim

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//By LYLtim#include<stdio.h>const int di[4] = {0,1,0,-1},          dj[4] = {1,0,-1,0};unsigned maze[5][5] = {2, 1, 0, 0, 0,0, 1, 0, 1, 0,0, 0, 0, 0, 0,0, 1, 1, 1, 0,0, 0, 0, 1, 0},head = 0, tail = 1;struct { int i, j; } que[23] = {0};void print_maze(void){int i, j;for (i = 0; i < 5; i++) {for (j = 0; j < 5; j++)printf("%d ", maze[i][j]);putchar('\n');}printf("*********\n");}int main(void){while (head != tail) {head = (head + 1) % 23;int i;for (i = 0; i < 4; i++)if (que[head].i + di[i] >= 0 && que[head].i + di[i] < 5&& que[head].j + dj[i] >= 0 && que[head].j +dj[i] < 5&& maze[que[head].i + di[i]][que[head].j +dj[i]] == 0) {que[tail = (tail + 1) % 23].i = que[head].i + di[i];que[tail].j = que[head].j +dj[i];maze[que[head].i + di[i]][que[head].j +dj[i]] = 2;if (que[head].i + di[i] == 4 && que[head].j +dj[i] == 4) {printf("Have path.\n"); exit(0);}}print_maze();}printf("No path.\n");return 0;}


运行结果如下:

2 1 0 0 0 2 1 0 1 0 0 0 0 0 0 0 1 1 1 0 0 0 0 1 0 *********2 1 0 0 0 2 1 0 1 0 2 0 0 0 0 0 1 1 1 0 0 0 0 1 0 *********2 1 0 0 0 2 1 0 1 0 2 2 0 0 0 2 1 1 1 0 0 0 0 1 0 *********2 1 0 0 0 2 1 0 1 0 2 2 2 0 0 2 1 1 1 0 0 0 0 1 0 *********2 1 0 0 0 2 1 0 1 0 2 2 2 0 0 2 1 1 1 0 2 0 0 1 0 *********2 1 0 0 0 2 1 2 1 0 2 2 2 2 0 2 1 1 1 0 2 0 0 1 0 *********2 1 0 0 0 2 1 2 1 0 2 2 2 2 0 2 1 1 1 0 2 2 0 1 0 *********2 1 0 0 0 2 1 2 1 0 2 2 2 2 2 2 1 1 1 0 2 2 0 1 0 *********2 1 2 0 0 2 1 2 1 0 2 2 2 2 2 2 1 1 1 0 2 2 0 1 0 *********2 1 2 0 0 2 1 2 1 0 2 2 2 2 2 2 1 1 1 0 2 2 2 1 0 *********2 1 2 0 0 2 1 2 1 2 2 2 2 2 2 2 1 1 1 2 2 2 2 1 0 *********2 1 2 2 0 2 1 2 1 2 2 2 2 2 2 2 1 1 1 2 2 2 2 1 0 *********2 1 2 2 0 2 1 2 1 2 2 2 2 2 2 2 1 1 1 2 2 2 2 1 0 *********Have path.

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