函数的结构体指针参数传递的问题 都忘完了

memset
  <memory.h>   or   <string.h>

void swap(int *p1,int *p2){*p1=5;*p2=6;}...int a=3,b=4;int *pa=&a,*pb=&b;swap(pa,pb); //或者swap（&a,&b);

struct   student{
        char   *last_name;
        int     student_id;
        char   grade;
}

struct   student   temp,   *p   =   &temp;
temp.grade   =   'A ';
temp.last_name   =   "Bushker ";
temp.student_id   =   590017;

其中
temp.grade   等价于   p-> grade.值是A
temp.last_name   等价于   p-> last_name.值是Bushker
temp.student_id   等价于   p-> student_id.值是590017
(*p).grade   等价于   p-> student_id.值是590017

这样看来,-> 用于结构指针指向的结构的成员.而结构实体用.指向成员.是这样理解对吧?

#include"stdio.h"#include"string.h"#define Max 100typedef struct{char data[Max];int top;}SqStack;void zhikong(SqStack *s){      //将栈置空.s->top=-1;memset(s->data,0,100);}int push(SqStack *s, char e){  //进栈if(s->top==Max-1){printf("栈满\n");return 0;}s->top++;s->data[s->top]=e;return 1;}int pop(SqStack *s, char *e){   //出栈if(s->top==-1){printf("栈空\n");return 0;}*e=s->data[s->top--];return 1;}int judge(char a[]){      //判断是否是对称串int i;char e;SqStack s;zhikong(&s);for(i = 0; a[i]!='\n'; i++){push(&s,a[i]);}for(i = 0;a[i]!='\n';i++){pop(&s,&e);if(a[i]!=e)return 0;}return 1;}int main(){char a[Max]="";int i=-1,n;do{i++;scanf("%c",&a[i]);}while(a[i]!='\n');n=judge(a);if(n==1)printf("该字符串为对称串\n");elseprintf("该字符串不为对称串\n");return 0;}