usaco Electric Fence
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这道题比较简单。
不过还是得注意考虑几种特殊情况,如下所示:
还有就是得去掉相交的点即可。
代码如下:
/*ID: guo geerPROG: fence9LANG: C++*/#include<iostream>#include<fstream>#include<cstdio>#include<cstring>#include<string>#include<cmath>using namespace std;int main(){ freopen("fence9.in","r",stdin); freopen("fence9.out","w",stdout); int n, m, p; while(scanf("%d %d %d", &n,&m,&p)==3) { int res = 0; if(n != 0) { for(int i=1; i<n; i++) { res += (i*m)/n; if((i*m)%n == 0) res --; } } if(n < p) { for(int i=1; i<p-n; i++) { res += (i*m)/(p-n); if((i*m)%(p-n) == 0) res --; } } else if(n > p) { for(int i=1; i<n-p; i++) { res -= (i*m)/(n-p); } } if(n>0&&p>n) res += m-1; printf("%d\n", res); } return 0;}
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