JAVA集合操作的利器:CollectionUtils

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【IT168 技术】使用 CollectionUtils 中四个方法之一执行集合操作.这四种分别是 union(),intersection();disjunction(); subtract();

  下列例子就是演示了如何使用上述四个方法处理两个 Collection;

  注: 这些方法都是数学的集合算法

import java.util.Arrays;      
import java.util.Collection;      
import java.util.Collections;      
import java.util.List;              
import org.apache.commons.collections.CollectionUtils;  import org.apache.commons.lang.ArrayUtils;            
  
public class CollectionUtilsIntro {    
  @SuppressWarnings(
"unchecked")      
  
public static void main(String[] args) {      
   String[] arrayA
=new String[] {"1","2","3","3","4","5" };      
   String[] arrayB
=new String[] {"3","4","4","5","6","7" };              
   List
<String> a= Arrays.asList(arrayA);      
   List
<String> b= Arrays.asList(arrayB);      
  
//并集      
   Collection<String> union= CollectionUtils.union(a, b);      
  
//交集      
   Collection<String> intersection= CollectionUtils.intersection(a, b);      
  
//交集的补集      
   Collection<String> disjunction= CollectionUtils.disjunction(a, b);      
  
//集合相减      
   Collection<String> subtract= CollectionUtils.subtract(a, b);              
   Collections.sort((List
<String>) union);      
   Collections.sort((List
<String>) intersection);      
   Collections.sort((List
<String>) disjunction);      
   Collections.sort((List
<String>) subtract);              
   System.out.println(
"A:" + ArrayUtils.toString(a.toArray()));      
   System.out.println(
"B:" + ArrayUtils.toString(b.toArray()));      
   System.out.println(
"--------------------------------------------");      
   System.out.println(
"Union(A, B):" + ArrayUtils.toString(union.toArray()));      
   System.out.println(
"Intersection(A, B):" + ArrayUtils.toString(intersection.toArray()));      
   System.out.println(
"Disjunction(A, B):" + ArrayUtils.toString(disjunction.toArray()));      
   System.out.println(
"Subtract(A, B):" + ArrayUtils.toString(subtract.toArray()));      
  }      
}

 

  输出如下:

  A: {1,2,3,3,4,5}

  B: {3,4,4,5,6,7}

  --------------------------------------------

  Union(A, B): {1,2,3,3,4,4,5,6,7}

  Intersection(A, B): {3,4,5}

  Disjunction(A, B): {1,2,3,4,6,7}

  Subtract(A, B): {1,2,3}


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