判断数字回文

#include<iostream>using namespace std;bool IsPalindrome(int n)//n 是要判断的数字{int s=0,m=n;while(m){s=s*10+m%10;m/=10;}if(s==n)return true;}int main(){int n;while(n){cin>>n;if(IsPalindrome(n))cout<<"Yes"<<endl;elsecout<<"No"<<endl;}return 0;}