2027 统计元音

来源：互联网发布：三国名将法宝进阶数据编辑：程序博客网时间：2024/05/03 15:53

#include<iostream>#include<cstdio>using namespace std;int main(void){    int n;    cin>>n;    getchar();    string str;    int aCount,eCount,iCount,oCount,uCount;    while(n--)    {        getline(cin,str);        aCount=eCount=iCount=oCount=uCount=0;        for(int i=0;i<str.length();i++)        {            if(str[i]=='a')            {                aCount++;            }            else if(str[i]=='e')            {                eCount++;            }            else if(str[i]=='i')            {                iCount++;            }            else if(str[i]=='o')            {                oCount++;            }            else if(str[i]=='u')            {                uCount++;            }        }        cout<<"a:"<<aCount<<endl;        cout<<"e:"<<eCount<<endl;        cout<<"i:"<<iCount<<endl;        cout<<"o:"<<oCount<<endl;        cout<<"u:"<<uCount<<endl;        if(n!=0)        {            cout<<endl;        }    }    return 0;}