project Euler第六题

题目：

The sum of the squares of the first ten natural numbers is,

1² + 2² + ... + 10² = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)² = 55² = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025  385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

算法：

#!usr/bin/env python#coding=utf-8a = 100*(100+1)*(200+1)/6b = (1+100)*50b = b**2print b-a

结果：

25164150

这个题没啥说的，就是两个数学公式