oracle自定义函数验证身份证是否合法

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--身份证号校验位算法:           1:把前17位号码从第高位到低位与下列17个数字分别相乘求和(N):               『2,4,8,5,10,9,7,3,6,1,2,4,8,5,10,9,7』                比如身份证号码为:C1C2C3……C16C17                则N=C17×2+C16×4+……+C1×7;           2:将N除以11取余数R,根据余数计算校验位T:                1)如果R=0,则T=1;如果R=1,则T=0;如果R=2,则T=X;                2)如果R=3,则T=9;如果R=4,则T=8;依此类推……;如果R=10,则T=2;-- 0代表身份证不合法,1代表身份证合法create or replace function CHECK_IDCARD(p_idcard varchar2) return number is   v_regstr      VARCHAR2 (2000);   v_sum         NUMBER;   v_mod         NUMBER;   v_checkcode   CHAR (11)       := '10X98765432';   v_checkbit    CHAR (1);   v_areacode    VARCHAR2 (2000)      := '11,12,13,14,15,21,22,23,31,32,33,34,35,36,37,41,42,43,44,45,46,50,51,52,53,54,61,62,63,64,65,71,81,82,91,';BEGIN   CASE LENGTHB (p_idcard)      WHEN 15      THEN                                                            -- 验证15位身份证         IF INSTRB (v_areacode, SUBSTR (p_idcard, 1, 2) || ',') = 0         THEN            RETURN 0;         END IF;         IF    MOD (TO_NUMBER (SUBSTR (p_idcard, 7, 2)) + 1900, 400) = 0            OR (    MOD (TO_NUMBER (SUBSTR (p_idcard, 7, 2)) + 1900, 100) <>                                                                             0                AND MOD (TO_NUMBER (SUBSTR (p_idcard, 7, 2)) + 1900, 4) = 0               )         THEN                                                          -- 闰年            v_regstr :=               '^[1-9][0-9]{5}[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9]))[0-9]{3}$';         ELSE            v_regstr :=               '^[1-9][0-9]{5}[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8]))[0-9]{3}$';         END IF;         IF REGEXP_LIKE (p_idcard, v_regstr)         THEN            RETURN 1;         ELSE            RETURN 0;         END IF;      WHEN 18      THEN                                                             --验证 18位身份证         IF INSTRB (v_areacode, SUBSTR (p_idcard, 1, 2) || ',') = 0         THEN            RETURN 0;         END IF;         IF    MOD (TO_NUMBER (SUBSTR (p_idcard, 7, 4)), 400) = 0            OR (    MOD (TO_NUMBER (SUBSTR (p_idcard, 7, 4)), 100) <> 0                AND MOD (TO_NUMBER (SUBSTR (p_idcard, 7, 4)), 4) = 0               )         THEN                                                          -- 闰年            v_regstr :=               '^[1-9][0-9]{5}19[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9]))[0-9]{3}[0-9Xx]$';         ELSE            v_regstr :=               '^[1-9][0-9]{5}19[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8]))[0-9]{3}[0-9Xx]$';         END IF;         IF REGEXP_LIKE (p_idcard, v_regstr)         THEN            v_sum :=                   (  TO_NUMBER (SUBSTRB (p_idcard, 1, 1))                    + TO_NUMBER (SUBSTRB (p_idcard, 11, 1))                   )                 * 7               +   (  TO_NUMBER (SUBSTRB (p_idcard, 2, 1))                    + TO_NUMBER (SUBSTRB (p_idcard, 12, 1))                   )                 * 9               +   (  TO_NUMBER (SUBSTRB (p_idcard, 3, 1))                    + TO_NUMBER (SUBSTRB (p_idcard, 13, 1))                   )                 * 10               +   (  TO_NUMBER (SUBSTRB (p_idcard, 4, 1))                    + TO_NUMBER (SUBSTRB (p_idcard, 14, 1))                   )                 * 5               +   (  TO_NUMBER (SUBSTRB (p_idcard, 5, 1))                    + TO_NUMBER (SUBSTRB (p_idcard, 15, 1))                   )                 * 8               +   (  TO_NUMBER (SUBSTRB (p_idcard, 6, 1))                    + TO_NUMBER (SUBSTRB (p_idcard, 16, 1))                   )                 * 4               +   (  TO_NUMBER (SUBSTRB (p_idcard, 7, 1))                    + TO_NUMBER (SUBSTRB (p_idcard, 17, 1))                   )                 * 2               + TO_NUMBER (SUBSTRB (p_idcard, 8, 1)) * 1               + TO_NUMBER (SUBSTRB (p_idcard, 9, 1)) * 6               + TO_NUMBER (SUBSTRB (p_idcard, 10, 1)) * 3;            v_mod := MOD (v_sum, 11);            v_checkbit := SUBSTRB (v_checkcode, v_mod + 1, 1);            IF v_checkbit = SUBSTRB (p_idcard, 18, 1)            THEN               RETURN 1;            ELSE               RETURN 0;            END IF;         ELSE            RETURN 0;         END IF;      ELSE         RETURN 0;                                      -- 身份证号码位数不对   END CASE;EXCEPTION   WHEN OTHERS   THEN      RETURN 0;end CHECK_IDCARD;