joj1889

 1889: A multiplication game

---

ResultTIME LimitMEMORY LimitRun TimesAC TimesJUDGE3s8192K362139Standard

Stan and Ollie play the game of multiplication by multiplying an integer p by one of the numbers 2 to 9. Stan always starts with p = 1, does his multiplication, then Ollie multiplies the number, then Stan and so on. Before a game starts, they draw an integer 1 < n < 4294967295 and the winner is who first reaches p >= n. Each line of input contains one integer number n. For each line of input output one line either

Stan wins.

or

Ollie wins.

assuming that both of them play perfectly. There should be one more blank line at the end of your output.

Sample input

1621734012226

Output for sample input

Stan wins.Ollie wins.Stan wins.

---

Submit / Problem List / Status / Discuss

这个题目的关键是了解博弈算法当中的关于最大最小策略。这既是一个博弈论的问题又是一个离散数学的问题。

#include <iostream>
#include<stdio.h>
using namespace std;


int main()
{
    int n;
    while(scanf("%d",&n)==1)
    {
        int p=1;
        while(p<n)
        {
            p=p*9;
            if(p>=n)
            {
                cout<<"Stan wins."<<endl;
                break;
            }
            p=p*2;
            if(p>=n)
            {
                cout<<"Ollie wins."<<endl;;
                break;
            }
        }
    }
    cout<<endl;
    return 0;
}