POJ 1008 解题报告 Maya Calendar
来源:互联网 发布:ps cs6色环插件 mac 编辑:程序博客网 时间:2024/06/07 04:55
还是要细心啊,题目不难,历法转换。
AC吧,这么简单的题烧这么长时间。。。丢人了。。。。
#include <iostream>#include <string>#include <cstdlib>#include <cstdio>using namespace std;int getTotalDays(string&, string&, string&);string& turnHolly(int, string&);int main (){int iCount;cin >> iCount;cout << iCount << endl;string strDayHaab;string strMonthHaab;string strYearHaab;int iTotalDays;while (iCount --){cin >> strDayHaab >> strMonthHaab >> strYearHaab;strDayHaab = strDayHaab.substr(0, strDayHaab.find("."));iTotalDays = getTotalDays(strDayHaab, strMonthHaab, strYearHaab);string strResult = "";cout << turnHolly(iTotalDays, strResult) << endl;}return 0;}int getTotalDays(string& strDayHaab, string& strMonthHaab, string& strYearHaab){int iTotalDays = atoi(strDayHaab.c_str());if ("pop" == strMonthHaab){}else if ("no" == strMonthHaab){iTotalDays += 1*20;}else if ("zip" == strMonthHaab){iTotalDays += 2*20;}else if ("zotz" == strMonthHaab){iTotalDays += 3*20;}else if ("tzec" == strMonthHaab){iTotalDays += 4*20;}else if ("xul" == strMonthHaab){iTotalDays += 5*20;}else if ("yoxkin" == strMonthHaab){iTotalDays += 6*20;}else if ("mol" == strMonthHaab){iTotalDays += 7*20;}else if ("chen" == strMonthHaab){iTotalDays += 8*20;}else if ("yax" == strMonthHaab){iTotalDays += 9*20;}else if ("zac" == strMonthHaab){iTotalDays += 10*20;}else if ("ceh" == strMonthHaab){iTotalDays += 11*20;}else if ("mac" == strMonthHaab){iTotalDays += 12*20;}else if ("kankin" == strMonthHaab){iTotalDays += 13*20;}else if ("muan" == strMonthHaab){iTotalDays += 14*20;}else if ("pax" == strMonthHaab){iTotalDays += 15*20;}else if ("koyab" == strMonthHaab){iTotalDays += 16*20;}else if ("cumhu" == strMonthHaab){iTotalDays += 17*20;}else if ("uayet" == strMonthHaab){iTotalDays += 18*20;}else {cout << "Month count wrong!" << endl;}iTotalDays += 365 * atoi(strYearHaab.c_str());return iTotalDays;}string& turnHolly(int iTotalDays, string& strR){char cTemp[32];sprintf(cTemp, "%d", iTotalDays % 260 % 13 + 1);strR = string(cTemp);switch((iTotalDays % 260) % 20){case 0:strR.insert(strR.size(), " imix ");break;case 1:strR.insert(strR.size(), " ik ");break;case 2:strR.insert(strR.size(), " akbal ");break;case 3:strR.insert(strR.size(), " kan ");break;case 4:strR.insert(strR.size(), " chicchan ");break;case 5:strR.insert(strR.size(), " cimi ");break;case 6:strR.insert(strR.size(), " manik ");break;case 7:strR.insert(strR.size(), " lamat ");break;case 8:strR.insert(strR.size(), " muluk ");break;case 9:strR.insert(strR.size(), " ok ");break;case 10:strR.insert(strR.size(), " chuen ");break;case 11:strR.insert(strR.size(), " eb ");break;case 12:strR.insert(strR.size(), " ben ");break;case 13:strR.insert(strR.size(), " ix ");break;case 14:strR.insert(strR.size(), " mem ");break;case 15:strR.insert(strR.size(), " cib ");break;case 16:strR.insert(strR.size(), " caban ");break;case 17:strR.insert(strR.size(), " eznab ");break;case 18:strR.insert(strR.size(), " canac ");break;case 19:strR.insert(strR.size(), " ahau ");break;}sprintf(cTemp, "%d", (int)(iTotalDays / 260));strR += string(cTemp);return strR;}
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