c++基类不为虚析构函数的一个风险

#include <iostream>using namespace std;class Point {public:    //如果这里不写成虚拟的析构函数，子类就会有内存泄漏//virtual ~point()//{//cout<<"point out"<<endl;//}~Point(){cout<<"point out"<<endl;}};class Cson:public Point{public:char* data;Cson(){data = (char*)malloc(5);}~Cson(){cout<<"cson out"<<endl;free(data);data = NULL;}};int main(){Cson* son =  new(std::nothrow) Cson;Point* point = NULL;if (NULL != son){point = son;delete point;}system("pause");}//输出结果/*point out请按任意键继续. . .*///子类的析构函数根本没被调用，除非父类的析构函数被声明为virtual//当然直接delete son，肯定是会调用父类的析构函数的，就不存在问题