HDU1847 Good Luck in CET-4 Everybody! 博弈

/*HDU1847博弈SG函数3.可选步数为一系列不连续的数，用GetSG(计算)*/#include "SG.h"#include<iostream>using namespace std;int Array[MAX];int main(){int n,i,j = 1;for(i=1,j=1; j <= MAX;i++,j=j*2)Array[i] = j;Array[0] = i - 1;GetSG(Array);while(cin>>n){if(SG[n])cout<<"Kiki"<<endl;elsecout<<"Cici"<<endl;}               return 0;   }