c/c++求两个日期之间的间隔天数

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就不废话了，直接上程序：

ps:

day_distance_2中的逻辑哪位大神懂，请直接留言，感谢

/**参见msdn tm time_t注意有效范围，里面的year不能太早，否则计算不准确*/int day_distance_1(int year1,int month1,int day1,int year2,int month2,int day2){    struct tm tm1;tm1.tm_year = year1 - 1900;tm1.tm_mon = month1 - 1;tm1.tm_mday = day1;tm1.tm_hour = 0;tm1.tm_min = 0;tm1.tm_sec = 0;struct tm tm2;tm2.tm_year = year2 - 1900;tm2.tm_mon = month2 - 1;tm2.tm_mday = day2;tm2.tm_hour = 0;tm2.tm_min = 0;tm2.tm_sec = 0;time_t time1;time_t time2;time1 = mktime(&tm1);time2 = mktime(&tm2);double diff = difftime(time1,time2);return (int)(diff/(3600*24));}/**这个方法的计算范围很大，但是不清楚里面的算法内容，杯具...*/int day_distance_2(int year1,int month1,int day1,int year2,int month2,int day2){    int nd, nm, ny; //new_day, new_month, new_year    int od, om, oy; //old_day, oldmonth, old_year      nm = (month2 + 9) % 12;ny = year2 - nm/10;nd = 365*ny + ny/4 - ny/100 + ny/400 + (nm*306 + 5)/10 + (day2 - 1);  om = (month1 + 9) % 12;oy = year1 - om/10;od = 365*oy + oy/4 - oy/100 + oy/400 + (om*306 + 5)/10 + (day1 - 1);      return od - nd;}int main(){cout << day_distance_1(2012,1,14,2011,9,21) << endl;    cout << day_distance_2(2012,1,14,2011,9,21) << endl;}