如何使UIWebView响应Touch事件

来源：互联网发布：群晖网络存储器编辑：程序博客网时间：2024/06/04 18:44

UIWebView响应不了Touch事件，很久以前就很难解决。最后有一个叫做UICWebView的东西，虽然用了private api，但是可以用。不过－－－－UICWebView或者任何用UIWebDocumentView获得事件的方法在iOS4 100%会出错（因为UIWebDocumentView这个东西没了）。用下面的方法可以让UIWebView响应Touch事件，而且不会影响滚动拖拽的bouncing。

如果需要touch的个数或者坐标，也很简单，不过需要自己修改代码里的JavaScript。

- (void)viewDidLoad {    [super viewDidLoad];    self.webView.delegate=self;    NSString *resourcePath = [ [NSBundle mainBundle] resourcePath];    NSString *filePath = [resourcePath stringByAppendingPathComponent:@"test.html"];    NSString *htmlstring = [[NSString alloc] initWithContentsOfFile:filePath  encoding:NSUTF8StringEncoding error:nil];    NSString *newHTMLString =         [htmlstring stringByAppendingString:            @"<script language=\"javascript\">                document.ontouchstart =                     function(){                        document.location=\"myweb:touch:start\";                    };                 document.ontouchend =                     function(){                        document.location=\"myweb:touch:end\";                    };                document.ontouchmove =                    function(){                        document.location=\"myweb:touch:move\";                    }            </script>"        ];    [self.webView loadHTMLString:newHTMLString baseURL:[NSURL fileURLWithPath:[[NSBundle mainBundle] bundlePath]]];    [htmlstring release];}- (BOOL)webView:(UIWebView*)webView shouldStartLoadWithRequest:(NSURLRequest*)request navigationType:(UIWebViewNavigationType)navigationType {    NSString *requestString = [[request URL] absoluteString];    NSArray *components = [requestString componentsSeparatedByString:@":"];    if ([components count] > 1 && [(NSString *)[components objectAtIndex:0] isEqualToString:@"myweb"]) {        if([(NSString *)[components objectAtIndex:1] isEqualToString:@"touch"]) {            NSLog(@"%@",[components objectAtIndex:2]);        }        return NO;    }    return YES;}

原文地址：http://apps.hi.baidu.com/share/detail/40317282