1128. DICE

骰子模拟。

#include <iostream>#include <cstring>using namespace std;int main(){char arr[7],temp;while(cin>>arr+1){if(arr[5]=='1'||arr[6]=='1')//首先若1在上下面，将1反转至水平面{temp=arr[5];arr[5]=arr[4];arr[4]=arr[6];arr[6]=arr[3];arr[3]=temp;}while(arr[1]!='1')//将1转至东面{temp=arr[2];arr[2]=arr[4];arr[4]=arr[1];arr[1]=arr[3];arr[3]=temp;}while(arr[3]!='2')//将2固定至北面{temp=arr[5];arr[5]=arr[4];arr[4]=arr[6];arr[6]=arr[3];arr[3]=temp;}cout<<((arr[5]=='3')?"right":"left")<<endl;}return 0;}