js 模仿锚点定位
来源：互联网 发布：后台远程控制软件 编辑：程序博客网 时间：2024/05/16 13:22
<div class="designer-bg ov"> <div class="w-77 f-l designer-nav"> <ul id="scroll_nav"> <li class="designer-nav-li"><a href="" title="" data-nav="a">A - E</a></li> <li class="designer-nav-li"><a href="" title="" data-nav="f">F - L</a></li> <li class="designer-nav-li"><a href="" title="" data-nav="m">M - T</a></li> <li class="designer-nav-li"><a href="" title="" data-nav="u">U - Z</a></li> </ul> </div><script type="text/javascript">$(function(){var navLinks = $('#scroll_nav').find('a') , target_ul = $('#designer_nav_name') , _top = 0;$.each(navLinks , function( i , elem ){$(elem).attr('data-to' , i == 0 ? 0 : _top);var id = $(elem).attr('data-nav');var _h4 = $('#'+id).parent();_top = parseInt(_h4.next().height()) + _top + parseInt(_h4.height());$(elem).bind('click', function(){target_ul[0].scrollTop = $(this).attr('data-to');return false;});});$('#designer_nav_name li').click(function( e ){var designer_name_href= $(this).find('a').attr("href");$.getJSON("test.php?action=test&jsoncallback=?&testid="+testidhref,function(data){$('#Ttai').html(data.catwalk);});e.preventDefault();});})</script> <div class="f-r designer-index" id="designer_nav_name"><h4><a name="a" id="a"><strong>A</strong></a></h4><ul><li></li></ul><h4><a name="f" id="f"><strong>F</strong></a></h4><ul><li></li></ul>
<h4><a name="m" id="m"><strong>M</strong></a></h4><ul><li></li></ul>
<h4><a name="u" id="u"><strong>U</strong></a></h4><ul><li></li></ul>
</div> </div>
