Digital Library

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A Digital Library contains millions of books, stored according to their titles, authors, key words of their abstracts, publishers, and published years. Each book is assigned an unique 7-digit number as its ID. Given any query from a reader, you are supposed to output the resulting books, sorted in increasing order of their ID's.

Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer N (<=10000) which is the total number of books. Then N blocks follow, each contains the information of a book in 6 lines:

  • Line #1: the 7-digit ID number;
  • Line #2: the book title -- a string of no more than 80 characters;
  • Line #3: the author -- a string of no more than 80 characters;
  • Line #4: the key words -- each word is a string of no more than 10 characters without any white space, and the keywords are separated by exactly one space;
  • Line #5: the publisher -- a string of no more than 80 characters;
  • Line #6: the published year -- a 4-digit number which is in the range [1000, 3000].

It is assumed that each book belongs to one author only, and contains no more than 5 key words; there are no more than 1000 distinct key words in total; and there are no more than 1000 distinct publishers.

After the book information, there is a line containing a positive integer M (<=1000) which is the number of user's search queries. Then M lines follow, each in one of the formats shown below:

  • 1: a book title
  • 2: name of an author
  • 3: a key word
  • 4: name of a publisher
  • 5: a 4-digit number representing the year

Output Specification:

For each query, first print the original query in a line, then output the resulting book ID's in increasing order, each occupying a line. If no book is found, print "Not Found" instead.

Sample Input:
31111111The Testing BookYue Chentest code debug sort keywordsZUCS Print20113333333Another Testing BookYue Chentest code sort keywordsZUCS Print220122222222The Testing BookCYLLkeywords debug bookZUCS Print2201161: The Testing Book2: Yue Chen3: keywords4: ZUCS Print5: 20113: blablabla
Sample Output:
1: The Testing Book111111122222222: Yue Chen111111133333333: keywords1111111222222233333334: ZUCS Print11111115: 2011111111122222223: blablablaNot Found

solution:

#include<iostream>#include<fstream>#include<hash_map>#include<string>#include<sstream>#include<algorithm>using namespace std;using namespace __gnu_cxx;struct str_hash//哈希函数对象{size_t operator()(const string& str) const{unsigned long __h = 0;for(size_t i = 0;i < str.size();++ i)__h = 5 * __h + str[i];return size_t(__h);}};int main(){vector<string> num;//存储每个序号hash_multimap<string,int,str_hash> title,author,keywords,publisher,year; //存储搜索项到序号的hashstring x,t,a,k,p,y;int n;string dustbin;cin >> n;getline(cin,dustbin);for(int i = 0;i < n;++ i){getline(cin,x);getline(cin,t);getline(cin,a);getline(cin,k);getline(cin,p);getline(cin,y);num.push_back(x);title.insert(make_pair(t,i));author.insert(make_pair(a,i));publisher.insert(make_pair(p,i));year.insert(make_pair(y,i));size_t pos1 = 0;size_t pos2 = 0;while(pos2 != string::npos){pos2 = k.find(' ',pos1);string tmp = k.substr(pos1,pos2 - pos1);pos1 = pos2 + 1;keywords.insert(make_pair(tmp,i));}}cin >> n;getline(cin,dustbin);   vector<string> query;for(int i = 0;i < n;++ i){string tmp;getline(cin,tmp);query.push_back(tmp);}vector<string> result;ostringstream os;for(size_t i = 0;i < query.size();++ i){result.clear();os << query[i] << endl;int count;char c = (query[i])[0];string s = (query[i]).substr(3);hash_multimap<string,int,str_hash>::iterator it;switch(c){case '1':count = title.count(s);it = title.find(s);if(count > 0)for(int j = 0;j < count;++ j){result.push_back(num[it->second]);++ it;}if(result.size() > 0){sort(result.begin(),result.end());for(size_t j = 0;j < result.size();++ j){os << result[j];if(!((j == result.size() - 1) && (i == query.size() - 1)))os << endl;}}else{os << "Not Found";if(i != query.size() - 1)os << endl;}break;case '2':count = author.count(s);it = author.find(s);if(count > 0)for(int j = 0;j < count;++ j){result.push_back(num[it->second]);++ it;}if(result.size() > 0){sort(result.begin(),result.end());for(size_t j = 0;j < result.size();++ j){os << result[j];if(!((j == result.size() - 1) && (i == query.size() - 1)))os << endl;}}else{os << "Not Found";if(i != query.size() - 1)os << endl;}break;case '3':count = keywords.count(s);it = keywords.find(s);if(count > 0)for(int j = 0;j < count;++ j){result.push_back(num[it->second]);++ it;}if(result.size() > 0){sort(result.begin(),result.end());for(size_t j = 0;j < result.size();++ j){os << result[j];if(!((j == result.size() - 1) && (i == query.size() - 1)))os << endl;}}else{os << "Not Found";if(i != query.size() - 1)os << endl;}break;case '4':count = publisher.count(s);it = publisher.find(s);if(count > 0)for(int j = 0;j < count;++ j){result.push_back(num[it->second]);++ it;}if(result.size() > 0){sort(result.begin(),result.end());for(size_t j = 0;j < result.size();++ j){os << result[j];if(!((j == result.size() - 1) && (i == query.size() - 1)))os << endl;}}else{os << "Not Found";if(i != query.size() - 1)os << endl;}break;case '5':count = year.count(s);it = year.find(s);if(count > 0)for(int j = 0;j < count;++ j){result.push_back(num[it->second]);++ it;}if(result.size() > 0){sort(result.begin(),result.end());for(size_t j = 0;j < result.size();++ j){os << result[j];if(!((j == result.size() - 1) && (i == query.size() - 1)))os << endl;}}else{os << "Not Found";if(i != query.size() - 1)os << endl;}break;default:cout << "Not Found";if(i != query.size() - 1)cout << endl;break;}}cout << os.str();}