C参数传递的演示

#include<stdio.h>int doSth1(int i);int doSth2(int *i);int main(int argc, char **argv){int *k;*k = 0;int kk;kk = 0;doSth1(*k);doSth1(kk);printf("%d,%d\n",*k,kk);doSth2(k);doSth2(&kk);printf("%d,%d",*k,kk);return 0;}int doSth1(int i){i = 999;return 0;}int doSth2(int *i){*i = 999;return 0;}