第8周-任务1-方案1-复数类中运算符重载（成员函数实现）

来源：互联网发布：qt高级编程丁林松 ppt 编辑：程序博客网时间：2024/05/16 08:22

【题目】实现复数类中的运算符重载：定义一个复数类重载运算符+、-、*、/，使之能用于复数的加减乘除。
方案一：请用类的成员函数完成运算符的重载；

class Complex{public:Complex(){real=0;imag=0;}Complex(double r,double i){real=r;imag=i;}Complex operator+(Complex &c2);Complex operator-(Complex &c2);Complex operator*(Complex &c2);Complex operator/(Complex &c2);void display();private:double real;double imag;};//下面定义成员函数int main(){Complex c1(3,4),c2(5,-10),c3;cout<<"c1=";c1.display();cout<<"c2=";c2.display();c3=c1+c2;cout<<"c1+c2=";c3.display();c3=c1-c2;cout<<"c1-c2=";c3.display();c3=c1*c2;cout<<"c1*c2=";c3.display();c3=c1/c2;cout<<"c1/c2=";c3.display();system("pause");return 0;}

【讲解视频】

【参考解答】

#include <iostream>using namespace std;class Complex{public:Complex(){real=0;imag=0;}Complex(double r,double i){real=r;imag=i;}Complex operator+(Complex &c2);Complex operator-(Complex &c2);Complex operator*(Complex &c2);Complex operator/(Complex &c2);void display();private:double real;double imag;};//复数相加： (a+bi)+(c+di)=(a+c)+(b+d)i. Complex Complex::operator+(Complex &c2){Complex c;c.real=real+c2.real;c.imag=imag+c2.imag;return c;}//复数相减：(a+bi)-(c+di)=(a-c)+(b-d)i.Complex Complex::operator-(Complex &c2){Complex c;c.real=real-c2.real;c.imag=imag-c2.imag;return c;}//复数相乘：(a+bi)(c+di)=(ac－bd)+(bc+ad)i.Complex Complex::operator*(Complex &c2){Complex c;c.real=real*c2.real-imag*c2.imag;c.imag=imag*c2.real+real*c2.imag;return c;}//复数相除：(a+bi)/(c+di)=(ac+bd)/(c^2+d^2) +(bc-ad)/(c^2+d^2)i Complex Complex::operator/(Complex &c2){Complex c;c.real=(real*c2.real+imag*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);c.imag=(imag*c2.real-real*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);return c;}void Complex::display(){cout<<"("<<real<<","<<imag<<"i)"<<endl;}int main(){Complex c1(3,4),c2(5,-10),c3;cout<<"c1=";c1.display();cout<<"c2=";c2.display();c3=c1+c2;cout<<"c1+c2=";c3.display();c3=c1-c2;cout<<"c1-c2=";c3.display();c3=c1*c2;cout<<"c1*c2=";c3.display();c3=c1/c2;cout<<"c1/c2=";c3.display();system("pause");return 0;}