第八周实验报告（任务1-方案3）

来源：互联网发布：淘宝上怎么改评价编辑：程序博客网时间：2024/04/30 06:11

程序头部注释开始
* 程序的版权和版本声明部分
* Copyright (c) 2011, 烟台大学计算机学院学生
* All rights reserved.
* 文件名称：     用友元函数完成运算符重载
* 作    者：     郭广建
* 完成日期： 2012年    04 月  10     日
* 版本号： 1.0

题目介绍：

方案三：在方案二的基础上，扩展+、-、*、/运算符的功能，使之能与double型数据进行运算。设Complex c; double d; c?d和d?c的结果为将d视为实部为d的复数同c运算的结果（其中?为+、-、*、/之一）。

源程序：

#include<iostream>using namespace std;class Complex{public:    Complex(){real=0;imag=0;}    Complex(double r,double i){real=r;imag=i;}    friend Complex operator+(double d,Complex &c2);    friend Complex operator-(double d,Complex &c2);    friend Complex operator*(double d,Complex &c2);    friend Complex operator/(double d,Complex &c2);    friend Complex operator+(Complex &c2,double d);    friend Complex operator-(Complex &c2,double d);    friend Complex operator*(Complex &c2,double d);    friend Complex operator/(Complex &c2,double d);    void display();private:    double real;    double imag;};//下面定义成员函数Complex operator+(double d, Complex &c2){return Complex(d + c2.real , c2.imag);}Complex operator-(double d, Complex &c2){return Complex(d - c2.real , c2.imag);}Complex operator*(double d, Complex &c2){return Complex( d * c2.real ,d * c2.imag);}Complex operator/(double d, Complex &c2){return Complex(d / c2.real ,d / c2.imag);}Complex operator+(Complex &c2,double d){return Complex(c2.real+d, c2.imag);}Complex operator-(Complex &c2,double d){return Complex(c2.real-d, c2.imag);}Complex operator*(Complex &c2,double d){return Complex(c2.real*d ,c2.imag*d);}Complex operator/(Complex &c2,double d){    return Complex(c2.real/d , c2.imag/d);}void Complex::display(){cout << '(' << real << ',' << imag << ')' <<endl;} int main(){    double d = 3.14;    Complex c1(3,4),c2(5,-10),c3;    cout<<"c1=";    c1.display();    cout<<"c2=";    c2.display();    c3=d+c1;    cout<<"d+c1";    c3.display();    c3=d-c1;    cout<<"d-c1";    c3.display();    c3=d*c1;    cout<<"d*c1";    c3.display();    c3=d/c1;    cout<<"d/c2=";    c3.display();c3=c2+d;    cout<<"c2+d=";    c3.display();    c3=c2-d;    cout<<"c2-d=";    c3.display();    c3=c2*d;    cout<<"c2*d=";    c3.display();    c3=c2/d;    cout<<"c2/d=";    c3.display();      system("pause");    return 0;}

运行结果：