poj 百练2972（基础题）

参考例程代码

例子确实写的好

关键：其他进制数据转换为10进制 b2ten()

#include <stdio.h>#include <string.h>long b2ten(char *x, int b){int ret = 0;int len = strlen(x);for (int i = 0; i < len; ++i){if(x[i] - '0' >= b)return -1;ret *= b;ret += x[i] - '0';}return (long)ret;}int main(){int T;int i,j;char p[8],q[8],r[8];long palgo,qalgo,ralgo;scanf("%d",&T);while(T--){scanf("%s%s%s",&p,&q,&r);int b;for(b = 2; b <= 16; ++b){palgo = b2ten(p,b);qalgo = b2ten(q,b);ralgo = b2ten(r,b);if(palgo == -1 || qalgo == -1 || ralgo == -1)continue;if(palgo * qalgo == ralgo){printf("%d\n",b);break;}}if(b == 17)printf("0\n");}return 0 ;}