c++第八周【任务1-1】实现复数类中的运算符重载

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/* (程序头部注释开始)* 程序的版权和版本声明部分* Copyright (c) 2011, 烟台大学计算机学院学生 * All rights reserved.* 文件名称:   c++第八周【任务1-1】                         * 作    者: 李洪悬                             * 完成日期:   2012      年   4    月   11     日* 版 本 号:          * 对任务及求解方法的描述部分* 输入描述: * 问题描述:实现复数类中的运算符重载* 程序输出: * 程序头部的注释结束*/

【任务1】实现复数类中的运算符重载定义一个复数类重载运算符+、-、*、/,使之能用于复数的加减乘除。(1)方案一:请用类的成员函数完成运算符的重载;class Complex{public:Complex(){real=0;imag=0;}Complex(double r,double i){real=r;imag=i;}Complex operator+(Complex &c2);Complex operator-(Complex &c2);Complex operator*(Complex &c2);Complex operator/(Complex &c2);void display();private:double real;double imag;};//下面定义成员函数int main(){Complex c1(3,4),c2(5,-10),c3;cout<<"c1=";c1.display();cout<<"c2=";c2.display();c3=c1+c2;cout<<"c1+c2=";c3.display();c3=c1-c2;cout<<"c1-c2=";c3.display();c3=c1*c2;cout<<"c1*c2=";c3.display();c3=c1/c2;cout<<"c1/c2=";c3.display();system("pause");return 0;}(2)方案二:请用类的友元函数,而不是成员函数,完成上面提及的运算符的重载;(3)方案三:在方案二的基础上,扩展+、-、*、/运算符的功能,使之能与double型数据进行运算。设Complex c; double d; c?d和d?c的结果为将d视为实部为d的复数同c运算的结果(其中?为+、-、*、/之一)。另外,定义一目运算符-,-c相当于0-c。

#include < iostream >   using namespace std;  class Complex  {  public:     Complex()   {   real=0;   imag=0;   }      Complex (double r,double i){real=r;imag=i;}     Complex operator + (Complex &c2);    Complex operator - (Complex &c2);     Complex operator * (Complex &c2);     Complex operator / (Complex &c2);    void display();  private:     double real;     double imag;  };  //复数相加:  (a+bi)+(c+di)=(a+c)+(b+d)i.    Complex Complex::operator + (Complex &c2)  {      Complex c;     c.real = real + c2.real;     c.imag = imag + c2.imag;     return c;  }  //复数相减:(a+bi)-(c+di)=(a-c)+(b-d)i.   Complex Complex::operator - (Complex &c2)  {    Complex c;     c.real = real - c2.real;    c.imag = imag - c2.imag;     return c;  }  //复数相乘:(a+bi)(c+di)=(ac-bd)+(bc+ad)i.   Complex Complex::operator * (Complex &c2)  {     Complex c;     c.real = real * c2.real - imag * c2.imag;     c.imag = imag * c2.real + real * c2.imag;     return c;  }   //复数相除:(a+bi)/(c+di)=(ac+bd)/(c^2+d^2) +(bc-ad)/(c^2+d^2)i    Complex Complex::operator / (Complex  &c2)  {      Complex c;      c.real = (real * c2.real + imag * c2.imag) / (c2.real * c2.real + c2.imag * c2.imag);      c.imag = (imag * c2.real - real * c2.imag) / (c2.real * c2.real + c2.imag * c2.imag);      return c;  }   void Complex::display()  {     cout << "(" << real << " , " << imag << "i)" << endl;  }    int main()  {     Complex c1(3 , 4),c2(5 , -10),c3;     cout << " c1 = ";     c1.display();     cout << " c2 = ";     c2.display();     c3 = c1 + c2;     cout << " c1 + c2 = ";     c3.display();     c3 = c1 - c2;     cout << " c1 - c2 = ";     c3.display();     c3 = c1 * c2;     cout << " c1 * c2 = ";     c3.display ();     c3 = c1 / c2;     cout << " c1 / c2 = ";     c3.display ();     system ( " pause " );     return 0;  }