第九周实验报告(一)定义Time类中的<<、>>运算符的重载

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/*
* 程序的版权和版本声明部分
* Copyright (c) 2011, 烟台大学计算机学院学生 
* All rights reserved.
* 文件名称:定义Time类中的<<、>>运算符的重载,实现输入输出,改造源程序中对运算结果的显示方式,使程序读起来更自然。                            
* 作    者:  晁 阳                            
* 完成日期:  2012年 4 月 16 日
* 版 本 号: t.10         
 
* 对任务及求解方法的描述部分
* 代码实现
#include <iostream>   using namespace std;class CTime      {      private:          unsigned short int hour;    // 时          unsigned short int minute;  // 分          unsigned short int second;  // 秒      public:          CTime(int h=0,int m=0,int s=0);      //    void setTime(int h,int m,int s);               //比较运算符(二目)的重载          bool operator > (CTime &t);          bool operator < (CTime &t);          bool operator >= (CTime &t);          bool operator <= (CTime &t);          bool operator == (CTime &t);          bool operator != (CTime &t);          //二目运算符的重载          CTime operator+(CTime &c);  //返回c所规定的时、分、秒后的时间,例t1(8,20,25),t2(11,20,50),t1+t2为:41:15          CTime operator-(CTime &c);//对照+理解          CTime operator+(int s);//返回s秒后的时间          CTime operator-(int s);//返回s秒前的时间          //一目运算符的重载          CTime operator++(int);//后置++,下一秒          CTime operator++();//前置++,下一秒          CTime operator--(int);//后置--,前一秒          CTime operator--();//前置--,前一秒          //赋值运算符的重载               CTime operator+=(CTime &c);          CTime operator-=(CTime &c);          CTime operator+=(int s);//返回s秒后的时间          CTime operator-=(int s);//返回s秒前的时间 //重载流插入运算符“<<”    friend ostream& operator << (ostream&,CTime&);//重载流提取运算符“>>”friend istream& operator >> (istream&,CTime&);};CTime::CTime(int h,int m,int s)      {          hour=h;          minute=m;          second=s;      }      ostream& operator << (ostream&output,CTime&c){ output<<c.hour <<":"<<c.minute <<":"<<c.second <<endl; return output;}   istream& operator >> (istream& input,CTime & c){ input>>c.hour>>c.minute>>c.second;return input;}bool CTime::operator > (CTime &t)      {       if (hour>t.hour) return true;      if (hour<t.hour) return false;      if (minute>t.minute) return true;      if (minute<t.minute) return false;      if (second>t.second) return true;      return false;  }      bool CTime::operator < (CTime &t)      {          if(hour<t.hour)              return true;          else if(hour>t.hour)              return false;          else if(minute<t.minute )              return true;          else if(minute>t.minute )              return false;          else if(second<t.second )              return true;          else if(second>t.second )              return false;          return false;      }      bool CTime::operator >= (CTime &t)      {          CTime t1;          t1.hour =hour;          t1.minute =minute ;          t1.second =second ;          if (t1<t)              return false;          return true;      }      bool CTime::operator <= (CTime &t)      {          CTime t1;          t1.hour =hour;          t1.minute =minute ;          t1.second =second ;          if (t1>t)              return false;          return true;      }      bool CTime::operator == (CTime &t)      {          CTime t1;          t1.hour =hour;          t1.minute =minute ;          t1.second =second ;          if (t1>t)              return false;          if (t1<t)              return false;          return true;      }      bool CTime::operator != (CTime &t)      {          CTime t1;          t1.hour =hour;          t1.minute =minute ;          t1.second =second ;          if(t1==t)              return false;          return true;      }      //二目运算符的重载      CTime CTime::operator+(CTime &c)//返回c所规定的时、分、秒后的时间,例t1(8,20,25),t2(11,20,50),t1+t2为:41:15      {          CTime c2;        int time;            time = (hour * 3600 + minute * 60 + second) + (c.hour * 3600 + c.minute * 60 + c.second);            c2.hour = time / 3600;            time = time % 3600;            c2.minute = time / 60;            time = time % 60;            c2.second = time;            return c2;    }      CTime CTime::operator-(CTime &c)//对照+理解      {          CTime c2;         int time;          time = (hour * 3600 + minute * 60 + second) - (c.hour * 3600 + c.minute * 60 + c.second);          c2.hour = time / 3600;          time = time % 3600;          c2.minute = time / 60;          time = time % 60;          c2.second = time;          return c2;      }      CTime CTime::operator+(int s)//返回s秒后的时间      {          int time = hour * 3600 + minute * 60 + second + s;            hour = time / 3600;            time = time % 3600;            minute = time / 60;            time = time % 60;            second = time;              return (*this);  }      CTime CTime::operator-(int s)//返回s秒前的时间      {          int time = hour * 3600 + minute * 60 + second;          time = time - s;          hour = time / 3600;          time = time % 3600;          minute = time / 60;          time = time % 60;          second = time;          return (*this);     }      //一目运算符的重载      CTime CTime::operator++(int)//后置++,下一秒      {          CTime temp(*this);          second++;          if(second>=60)          {               second-=60;              ++minute;          }          return temp;      }      CTime CTime::operator++()//前置++,下一秒      {          if(++second>=60)          {              second-=60;              ++minute;          }          return *this;      }      CTime CTime::operator--(int)//后置--,前一秒      {          CTime temp(*this);          second--;          if(second<0)          {               second=59;              --minute;          }          return temp;      }      CTime CTime::operator--()//前置--,前一秒      {          if(--second<0)          {              second=59;              --minute;          }          return *this;      }      //赋值运算符的重载           CTime CTime::operator+=(CTime &c)      {          CTime t1,t;          t1.hour =hour;          t1.minute =minute ;          t1.second =second ;          t=t1+c;          hour=t.hour ;          minute=t.minute ;          second=t.second ;          return t;      }      CTime CTime::operator-=(CTime &c)      {          *this=*this-c;      return *this;      }      CTime CTime::operator+=(int s)//返回s秒后的时间      {          CTime t1,t;          t1.hour =hour;          t1.minute =minute ;          t1.second =second ;          t=t1+s;          hour=t.hour ;          minute=t.minute ;          second=t.second ;          return t;      }      CTime CTime::operator-=(int s)//返回s秒前的时间      {          *this=*this-s;      return *this;  }      void main()      {          CTime t1(8,20,25),t2(11,20,50),t;          int n; cout<<"请输入t1的时间:(以aa bb cc的格式输入)";cin>>t1;cout<<"请输入t2的时间:(以aa bb cc的格式输入)";cin>>t2;    cout<<"t1为:";          cout<<t1;          cout<<"t2为:";          cout<<t2;          cout<<"下面比较两个时间大小:\n";          if (t1>t2) cout<<"t1>t2"<<endl;          if (t1<t2) cout<<"t1<t2"<<endl;          if (t1==t2) cout<<"t1=t2"<<endl;           if (t1!=t2) cout<<"t1≠t2"<<endl;          if (t1>=t2) cout<<"t1≥t2"<<endl;          if (t1<=t2) cout<<"t1≤t2"<<endl;          cout<<endl;          cout<<"t1+t2的时间为:";          t=t1+t2;          cout<<t;          cout<<"t2-t1的时间为:";          t=t2-t1;          cout<<t;          cout<<endl;          cout<<"请输入您想增加的秒数:";          cin>>n;          t=t1+n;          cout<<"增加"<<n<<"秒后的时间为:";          cout<<t;          t=t1-n;          cout<<"增加"<<n<<"秒前的时间为:";          cout<<t;          cout<<endl;          cout<<"对t1后置++,结果为:";          t=t1++;          cout<<t;          cout<<"运算结束后,t1的值为:";          cout<<t1;          cout<<endl;          cout<<"对t1前置++,结果为:";          t=++t1;          cout<<t;          cout<<"运算结束后,t1的值为:";          cout<<t1;          cout<<endl;          cout<<"对t1后置--,结果为:";          t=t1--;          cout<<t;          cout<<"运算结束后,t1的值为:";          cout<<t1;          cout<<endl;          cout<<"对t1前置--,结果为:";          t=--t1;          cout<<t;          cout<<"运算结束后,t1的值为:";          cout<<t1;          cout<<endl;          cout<<"运算t1+=t2的结果为:";          t1+=t2;          cout<<t1;          cout<<endl;          cout<<"此时t1的值为:";          cout<<t1;          cout<<"此时t2的值为:";          cout<<t2;          cout<<endl;          cout<<"运算t1-=t2的结果为:";          t1-=t2;          cout<<t1;          cout<<"此时t1的值为:";          cout<<t1;          cout<<"此时t2的值为:";          cout<<t2;          cout<<endl;          cout<<"请输入您想增加的秒数:";          cin>>n;          t1+=n;          cout<<"t1增加"<<n<<"秒后的时间为:";          cout<<t1;          cout<<"t2增加"<<n<<"秒前的时间为:";          t2-=n;          cout<<t2;          cout<<endl;          }  
 
上机感言:任务一二三都是在原有基础上对功能的拓展,大部分复制上周的就是,上周的作业也是刚刚交上。以后要想完成作业在去干其他的事情,带着作业干其他的什么都干不好,总想着还有作业没做完。虽然不是为了完成作业去完成作业,但是在一件事情没有彻底解决之前就着手其他的事情,最终结果只能是什么都干不好啊!一件一件干,才能把事情干好····
 
 
 
    
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