第九周实验报告2

/* (程序头部注释开始) * 程序的版权和版本声明部分 * Copyright (c) 2012, 烟台大学计算机学院学生  * All rights reserved. * 文件名称：流运算符重载运算符（Complex类）  * 作 者： 刘程程 * 完成日期： 2012 年 4 月 17日 * 版 本 号： 1.054 * 对任务及求解方法的描述部分 ** 问题描 述：按第八周任务1，定义Complex类中的<<和>>运算符重载，实现时间的输入输出，改造原程序中的对运算结果显示方式，是程序读起来更自然。        * 程序输出： ......  * 程序头部的注释结束 */  #include <iostream>     using namespace std;    class Complex    {    public:        Complex(){real=0;imag=0;}        Complex(double r,double i){real=r;imag=i;}        Complex operator-();        friend ostream& operator << (ostream& output,Complex& c);      friend istream& operator >> (istream& input,Complex& c);      friend Complex operator+(Complex &c1, Complex &c2);        friend Complex operator+(double d1, Complex &c2);        friend Complex operator+(Complex &c1, double d2);        friend Complex operator-(Complex &c1, Complex &c2);        friend Complex operator-(double d1, Complex &c2);        friend Complex operator-(Complex &c1, double d2);        friend Complex operator*(Complex &c1, Complex &c2);        friend Complex operator*(double d1, Complex &c2);        friend Complex operator*(Complex &c1, double d2);        friend Complex operator/(Complex &c1, Complex &c2);        friend Complex operator/(double d1, Complex &c2);        friend Complex operator/(Complex &c1, double d2);           private:        double real;        double imag;    };    //实现输出的运算符重载ostream& operator << (ostream& output,Complex& c){output<<"("<<c.real;if(c.imag>=0) output<<"+";output<<c.imag<<"i)";return output;}//实现输入的运算符重载istream& operator >> (istream& input,Complex& c){  int a,b;  char sign,i;  do{  cout<<"input a complex number(a+bi或a-bi):";  input>>a>>sign>>b>>i;}while(!((sign=='+'||sign=='-')&&i=='i'));c.real=a;c.imag=(sign=='+')?b:-b;return input;}Complex Complex::operator-()    {        return(0-*this); //需要好好理解    }        //复数相加：(a+bi)+(c+di)=(a+c)+(b+d)i.      Complex operator+(Complex &c1, Complex &c2)    {        Complex c;        c.real=c1.real+c2.real;        c.imag=c1.imag+c2.imag;        return c;    }    Complex operator+(double d1, Complex &c2)  {   Complex c(d1,0);   return c+c2;//按一般的运算有点麻烦，这种运算节省编写者的时间，但可能机器效率会不佳。。。   }  Complex operator+(Complex &c1, double d2)  {   Complex c(d2,0);   return c1+c;  }  //复数相减：(a+bi)-(c+di)=(a-c)+(b-d)i.     Complex operator-(Complex &c1, Complex &c2)    {        Complex c;        c.real=c1.real-c2.real;        c.imag=c1.imag-c2.imag;        return c;    }    Complex operator-(double d1, Complex &c2)    {        Complex c(d1,0);        return c-c2;      }    Complex operator-(Complex &c1, double d2)    {        Complex c(d2,0);        return c1-c;    }    //复数相乘：(a+bi)(c+di)=(ac－bd)+(bc+ad)i.     Complex operator*(Complex &c1, Complex &c2)    {        Complex c;        c.real=c1.real*c2.real-c1.imag*c2.imag;        c.imag=c1.imag*c2.real+c1.real*c2.imag;        return c;    }    Complex operator*(double d1, Complex &c2)    {        Complex c(d1,0);        return c*c2;    }    Complex operator*(Complex &c1, double d2)    {        Complex c(d2,0);        return c1*c; //注意位置    }    //复数相除：(a+bi)/(c+di)=(ac+bd)/(c^2+d^2) +(bc-ad)/(c^2+d^2)i      Complex operator/(Complex &c1, Complex &c2)    {        Complex c;        c.real=(c1.real*c2.real+c1.imag*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);        c.imag=(c1.imag*c2.real-c1.real*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);        return c;    }    Complex operator/(double d1, Complex &c2)    {        Complex c(d1,0);        return c/c2;    }    Complex operator/(Complex &c1, double d2)    {        Complex c(d2,0);        return c1/c;    }    int main()    {        Complex c1,c2,c3;        double d=11;        cout<<"c1:";     cin>>c2;        cout<<"c2=";     cin>>c2;    cout<<"d="<<d<<endl;        cout<<"-c1="<<(-c1);       c3=c1+c2;        cout<<"c1+c2="<<c3<<endl;       cout<<"c1+d="<<(c1+d)<<endl;       cout<<"d+c1="<<(d+c1)<<endl;       c3=c1-c2;        cout<<"c1-c2="<<c3<<endl;       cout<<"c1-d="<<(c1-d)<<endl;       cout<<"d-c1="<<(d-c1)<<endl;        c3=c1*c2;        cout<<"c1*c2="<<(c1*c2)<<endl;       cout<<"c1*d="<<(c1*d)<<endl;       cout<<"d*c1="<<(d*c1)<<endl;      c3=c1/c2;        cout<<"c1/c2="<<(c1/c2)<<endl;       cout<<"c1/d="<<(c1/d)<<endl;       cout<<"d/c1="<<(d/c1)<<endl;         system("pause");        return 0;    }