WP7 实现Listbox中长按弹出ContextMenu效果，获取选中的ListBoxItem

1.在工程references中引入Microsoft.Phone.Controls.Toolkit。

2.在需要实现的页面（例如，demo.xaml）文件中加入toolkit声明如下：

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1. xmlns:toolkit="clr-namespace:Microsoft.Phone.Controls;assembly=Microsoft.Phone.Controls.Toolkit"   

3.在demo.xaml中加入实现代码如下：

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1. <!--ContentPanel - place additional content here-->  
2.         
3. <StackPanel x:Name="ContentPanel" Grid.Row="1" Margin="12,0,12,0" >  
4.           <Grid Background="Blue">  
5.               <TextBlock Text="Select a color from the Context Menu"/>  
6.     <ListBox x:Name="listBox">  
7.         <ListBox.ItemTemplate>  
8.             <DataTemplate>  
9.                 <StackPanel Orientation="Horizontal">  
10.                     <toolkit:ContextMenuService.ContextMenu>  
11.                         <toolkit:ContextMenu>  
12.                             <toolkit:MenuItem Header="Add Color" Click="MenuItem_Click"/>  
13.                             <toolkit:MenuItem Header="Remove Color" Click="MenuItem_Click"/>  
14.                         </toolkit:ContextMenu>  
15.                     </toolkit:ContextMenuService.ContextMenu>  
16.                     <Image Source="{Binding ImageUri}" Stretch="None" />  
17.                     <TextBlock Text="{Binding Text}" />  
18.                 </StackPanel>  
19.             </DataTemplate>  
20.         </ListBox.ItemTemplate>  
21.     </ListBox>  
22.           </Grid>  
23.   
24.       </StackPanel>  

最重要的想要获取MenuItem 点击后 Click要获取的当前的ListBoxItem

 private void delOne_Click(object sender, System.Windows.RoutedEventArgs e)
 {
      ListBoxItem item = scheduleItemList.ItemContainerGenerator.ContainerFromItem(((MenuItem)sender).DataContext) as ListBoxItem;
      //下面在可以操作该item了
 }