如何去掉Powered by ECShop v2.7.1

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如何去掉Powered by Ecshop v2.7.1

1.去掉标题上Powered by ECShop的字样如下:

在includes/lib_main.php找到lib_main.php文件,打开后,找到143行,将$page_title = $GLOBALS[’

_CFG’][’shop_title’] . ‘ - ‘ . ‘Powered by ECShop’;改为$page_title = $GLOBALS[’

_CFG’][’shop_title’];当然, . ‘ - ‘ . ‘Powered by ECShop’也可以修改为自己喜欢的文字.

2.修改底部"Powered by Ecshop 2.x.x"

ecshop根目录/themes/当前模板名/library/page_footer.lbi, 找到如下代码:

{insert name='query_info'} 
<a href="http://www.ecshop.com" target="_blank" style="font-size:10px">Powered by

ECShop

{$ecs_version}</a>

将颜色标记部分替换为自己内容.其中蓝色部分为版本信息。

2. 修改底部"Powered by Ecshop v2.7.1"

ecshop根目录/themes/当前模板名/library/page_footer.lbi, 找到如下代码:

只要把显示版权的代码

{foreach from=$lang.p_y item=pv}{$pv}{/foreach}{$licensed}

去掉,
底部就会用Powered by ECShop随机替换掉底部原有链接元素.

再打开js/common.js

找到这段代码：

onload = function()
{
    var link_arr = document.getElementsByTagName(String.fromCharCode(65));
    var link_str;
    var link_text;
    var regg, cc;
    var rmd, rmd_s, rmd_e, link_eorr = 0;
    var e = new Array(97, 98, 99,
                      100, 101, 102, 103, 104, 105, 106, 107, 108, 109,
                      110, 111, 112, 113, 114, 115, 116, 117, 118, 119,
                      120, 121, 122
                      );

try
{
 for(var i = 0; i < link_arr.length; i++)
 {
 link_str = link_arr[i].href;
 if (link_str.indexOf(String.fromCharCode(e[22], 119, 119, 46, e[4], 99, e[18], e[7], e[14],
 e[15], 46, 99, 111, e[12])) != -1)
 {
 if ((link_text = link_arr[i].innerText) == undefined)
 {
 throw "noIE";
 }
 regg = new RegExp(String.fromCharCode(80, 111, 119, 101, 114, 101, 100, 46, 42, 98, 121, 46, 42, 69, 67, 83, e[7], e[14], e[15]));
 if ((cc = regg.exec(link_text)) != null)
 {
 if (link_arr[i].offsetHeight == 0)
 {
 break;
 }
 link_eorr = 1;
 break;
 }
 }
 else
 {
 link_eorr = link_eorr ? 0 : link_eorr;
 continue;
 }
 }
} // IE
catch(exc)
{
 for(var i = 0; i < link_arr.length; i++)
 {
 link_str = link_arr[i].href;
 if (link_str.indexOf(String.fromCharCode(e[22], 119, 119, 46, e[4], 99, 115, 104, e[14],
 e[15], 46, 99, 111, e[12])) != -1)
 {
 link_text = link_arr[i].textContent;
 regg = new RegExp(String.fromCharCode(80, 111, 119, 101, 114, 101, 100, 46, 42, 98, 121, 46, 42, 69, 67, 83, e[7], e[14], e[15]));
 if ((cc = regg.exec(link_text)) != null)
 {
 if (link_arr[i].offsetHeight == 0)
 {
 break;
 }
 link_eorr = 1;
 break;
 }
 }
 else
 {
 link_eorr = link_eorr ? 0 : link_eorr;
 continue;
 }
 }
} // FF

try
{
    rmd = Math.random();
    rmd_s = Math.floor(rmd * 10);
    if (link_eorr != 1)
    {
      rmd_e = i - rmd_s;
      link_arr[rmd_e].href = String.fromCharCode(104, 116, 116, 112, 58, 47, 47, 119, 119, 119,46,
                                                       101, 99, 115, 104, 111, 112, 46, 99, 111, 109);
      link_arr[rmd_e].innerHTML = String.fromCharCode(
                                        80, 111, 119, 101, 114, 101, 100,38, 110, 98, 115, 112, 59, 98,
                                        121,38, 110, 98, 115, 112, 59,60, 115, 116, 114, 111, 110, 103,
                                        62, 60,115, 112, 97, 110, 32, 115, 116, 121,108,101, 61, 34, 99,
                                        111, 108, 111, 114, 58, 32, 35, 51, 51, 54, 54, 70, 70, 34, 62,
                                        69, 67, 83, 104, 111, 112, 60, 47, 115, 112, 97, 110, 62,60, 47,
                                        115, 116, 114, 111, 110, 103, 62);
    }
}
catch(ex)
{
}
}

删除这随机函数，即解决问题。