判断自己计算机的字节对齐大小

#include <stdio.h>#include <stdlib.h>#define N 80struct Student{    int age;    char sex[5];};int main(void){    struct Student student = {.age=10, .sex="yang"};    printf("sizeof student is %d\n", sizeof(student) );exit(EXIT_SUCCESS);}

如果显示的结果为：sizeof student is 10；则表明对齐的是2的倍数；

如果显示的结果为：sizeof student is 12；则表明对齐的是4的倍数；

如果显示的结果为：sizeof student is 16；则表明对齐的是8的倍数；