[UvaOJ - Getting Started] 10055 - Hashmat the Brave Warrior
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Problem A
Hashmat the brave warrior
Input: standard input
Output: standard output
Hashmat is a brave warrior whowith his group of young soldiers moves from one place to another to fightagainst his opponents. Before fighting he just calculates onething, the difference between his soldier number and the opponent's soldiernumber. From this difference he decides whether to fight or not. Hashmat'ssoldier number is never greater than his opponent.
InputThe input contains two integer numbers inevery line. These two numbers in each line denotes the number of soldiers inHashmat's army and his opponent's army or vice versa. The input numbers are notgreater than 2^32. Input is terminated by End of File.
Output
For each line of input,print the difference of number of soldiers between Hashmat's army and hisopponent's army. Each output should be in seperate line.
Sample Input:
10 1210 14
100 200
Sample Output:
24
100
Shahriar Manzoor
16-12-2000
程序要点:
The input numbers are notgreater than 2^32. : 在声明变量的时候要考虑类型 2 ^ 32 需要声明为long long
Input is terminated by End of File. : 需要判断scanf的返回值类型为EOF
代码:
02
03 int main()
04 {
05 long long hashmat = 0 ;
06 long long enemy = 0;
07
08 while (scanf("%lld %lld",&hashmat,&enemy)!= EOF);
09 {
10 if (hashmat >= enemy)
11 {
12 printf("%lld", (hashmat- enemy));
13 }
14 else
15 {
16 printf("%lld", (enemy- hashmat));
17 }
18 }
19
20 return 0;
21 }
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