写一函数,取汉字

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create or replace function get_chinese
(
p_name in varchar2,
p_chinese in varchar2
) return varchar2
as
v_code varchar2(30000) := '';
v_chinese varchar2(4000) := '';
v_non_chinese varchar2(4000) := '';
v_comma pls_integer;
v_code_q pls_integer;
v_code_w pls_integer;
begin
if p_name is not null then
select replace(substrb(dump(p_name,1010),instrb(dump(p_name,1010),'ZHS16GBK:')),'ZHS16GBK: ','') into v_code from dual where rownum=1;
for i in 1..length(p_name) loop
if lengthb(substr(p_name,i,1))=2 then
v_comma := instrb(v_code,',');
v_code_q := to_number(substrb(v_code,1,v_comma-1));
v_code_w := to_number(substrb(v_code,v_comma+1,abs(instrb(v_code,',',1,2)-v_comma-1)));
if v_code_q>=176 and v_code_q<=247 and v_code_w>=161 and v_code_w<=254 then
v_chinese := v_chinese||substr(p_name,i,1);
else
v_non_chinese := v_non_chinese||substr(p_name,i,1);
end if;
v_code := ltrim(v_code,'1234567890');
v_code := ltrim(v_code,',');
else
v_non_chinese := v_non_chinese||substr(p_name,i,1);
end if;
v_code := ltrim(v_code,'1234567890');
v_code := ltrim(v_code,',');
end loop;
if p_chinese = '1' then
return v_chinese;
else
return v_non_chinese;
end if;
else
return '';
end if;
end;
/

或者:
select regexp_replace('孟梁(23)4','[^[:alpha:]]|[a-z,A-Z]','') as result from dual

例子:
SQL> select get_chinese(name,1) from a;

GET_CHINESE(NAME,1)
-----------------------------------------
我的个神
哎呀
中奖了

SQL> select get_chinese(name,0) from a;

GET_CHINESE(NAME,0)
-----------------------------------------

()★
\@

SQL>

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