动态建立链表
来源:互联网 发布:淘宝网修身连衣裙 编辑:程序博客网 时间:2024/04/29 07:41
所谓动态链表是指在程序执行过程中从无到有地建立起一个链表,既一个一个地开辟结点和输入各结点的数据,并建立起前后相连的关系。
例题:
#include <iostream>
using namespace std;
#define NULL0
struct student
{long num;
float score;
struct student *next;
};
int main()
{student a,b,c,*head,*p;
a.num=10001; a.score=89.5;
b.num=10003; b.score=90;
c.num=10007;c.score=85;
head=&a;
a.next=&b;
b.next=&c;
c.next=NULL;
p=head;
do
return 0;
}
1.针对例子写一个函数creat,用来建立一个动态链表。各结点的数据由键盘输入。
#include <iostream>
using namespace std;
#define NULL0
struct student
{long num;
float score;
student *next;
};
student*creat(void)
{student *head;
student *p1,*p2;
int n=0;
p1=p2=newstudent;
cin>>p1->num>>p1->score;
head=NULL;
while(p1->num!=0)
{n=n+1;
if(n==1) head=p1;
else p2->next=p1;
p2=p1;
p1=new student;
cin>>p1->num>>p1->score;
}
p2->next=NULL;
return(head);
}
2.写一个函数print,将上题建立的链表中各结点的数据依次输出。
#include <iostream>
using namespace std;
#define NULL0
struct student
{long num;
float score;
student *next;
};
intn;
void print(student *head)
{student *p;
cout<<"Now,These"<<n<<"records are:"<<endl;
p=head;
if(head!=NULL)
do
}while(p!=NULL);
}
3.写一个函数del,用来删除动态链表中的一个指定的结点(由实参指定某一学号,表示要删除该学生结点)。
#include <iostream>
using namespace std;
#define NULL0
struct student
{long num;
float score;
student *next;
};
intn;
student *del(student *head,long num)
{student *p1,*p2;
if(head==NULL)
{cout<<"listnull!"<<endl; return(head);}
{p2=p1;p1=p1->next;}
if(num==p1->num)
{if(p1==head)head=p1->next;
elsep2->next=p1->next;
cout<<"delete:"<<num<<endl;
n=n-1;
}
else cout<<"cannot find"<<num;
return(head);
}
4.写一个函数insert,用来向动态链表插入一个结点。
#include <iostream>
using namespace std;
#define NULL0
struct student
{long num;
float score;
student*next;
};
int n;
student *insert(student *head,student *stud)
{student *p0,*p1,*p2;
p1=head;
p0=stud;
if(head==NULL)
{head=p0;p0->next=NULL;}
else
{while((p0->num>p1->num)&&(p1->next!=NULL))
{p2=p1;
p1=p1->next;}
if(p0->num<=p1->num)
{if(head==p1)head=p0;
else
{p1->next=p0; p0->next=NULL;}}//插到最后的结点之后
}
5.将以上4个函数组成的程序,由主程序先后调用这些函数,实现链表的建立、输出、删除、和插入、在主程序中指定需要删除和插入的结点。
解一:
#include <iostream>
using namespace std;
#define NULL0
struct student
{long num;
float score;
student *next;
};
int n;
int main()
{ student *creat(void);
student *del(student *,long);
student *insert(student *,student *);
void print(student *);
student *head,*stu;
long del_num;
cout<<"inputrecords:"<<endl;
head=creat();
print(head);
cout<<endl<<"inputthe deleted number:";
cin>>del_num;
while(del_num!=0)
{head=del(head,del_num);
}
cout<<endl<<"inputthe inserted record:"; //输入要插入的结点
stu=newstudent;
cin>>stu->num>>stu->score;
while(stu->num!=0)
{head=insert(head,stu);
}
return 0;
}
student*creat(void)
{student *head;
student *p1,*p2;
n=0;
p1=p2=newstudent;
cin>>p1->num>>p1->score;
head=NULL;
while(p1->num!=0)
{n=n+1;
if(n==1) head=p1;
else p2->next=p1;
p2=p1;
p1=new student;
cin>>p1->num>>p1->score;
}
p2->next=NULL;
return(head);
}
student *del(student *head,longnum)
{student *p1,*p2;
if(head==NULL)
{cout<<"listnull!"<<endl; return(head);}
p1=head;
while(num!=p1->num&& p1->next!=NULL)//p1指向的不是所要找的结点且后面还有结点
{p2=p1;p1=p1->next;}
if(num==p1->num)
{if(p1==head)head=p1->next;
elsep2->next=p1->next;
cout<<"delete:"<<num<<endl;
n=n-1;
}
else cout<<"cannot find"<<num;
return(head);
}
student *insert(student *head,student *stud) //插入结点的函数
{student *p0,*p1,*p2;
p1=head;
p0=stud;
if(head==NULL)
{head=p0;p0->next=NULL;}
else
{while((p0->num>p1->num)&&(p1->next!=NULL))
{p2=p1;
p1=p1->next;}
if(p0->num<=p1->num)
{if(head==p1)head=p0;
else
{p1->next=p0; p0->next=NULL;}}//插到最后的结点之后