几种最最简单的解析XML的示例代码

来源：互联网发布：mac qq远程控制编辑：程序博客网时间：2024/05/17 03:58

private void button1_Click(object sender, EventArgs e)
{

            string xml = @"<root>
                            <row><id>1</id><name>项目1</name></row>
                            <row><id>2</id><name>项目2</name></row>
                            <row><id>3</id><name>项目3</name></row>
                            <row><id>4</id><name>项目4</name></row>
                        </root>";

            // 找出 ID = 2 的项目名
            XmlDocument doc = new XmlDocument();
            doc.LoadXml(xml);

string xpath = "//row[id=2]/name"; //两个斜杠表示不在乎具体层级

XmlNode node = doc.SelectSingleNode(xpath);

            if (node != null)
            {
                MessageBox.Show(node.InnerText);
            }
        }

        private void button2_Click(object sender, EventArgs e)
        {
            string xml = "<员工基本信息><姓名>张三</姓名><性别>男</性别><年龄>22岁</年龄></员工基本信息>";

            // 解析年龄
            XmlDocument doc = new XmlDocument();
            doc.LoadXml(xml);
            string xpath = "/员工基本信息/年龄";

XmlNode node = doc.SelectSingleNode(xpath);

            if (node != null)
            {
                MessageBox.Show(node.InnerText);
            }
        }

        private void button3_Click(object sender, EventArgs e)
        {
            string xml = @"<root>
                            <row id=""1""><name>项目1</name></row>
                            <row id=""2""><name>项目2</name></row>
                            <row id=""3""><name>项目3</name></row>
                        </root>";

            // 找出 row id = 2对应的name
            XmlDocument doc = new XmlDocument();
            doc.LoadXml(xml);

string xpath = "//row[@id=2]/name";

XmlNode node = doc.SelectSingleNode(xpath);

            if (node != null)
            {
                MessageBox.Show(node.InnerText);
            }
        }

        private void button4_Click(object sender, EventArgs e)
        {
            string xml = @"<root>
                            <row id=""1""><name pm=""汤姆"">项目1</name></row>
                            <row id=""2""><name pm=""杰瑞"">项目2</name></row>
                            <row id=""3""><name pm=""薇薇安"">项目3</name></row>
                        </root>";

            // 找出 row id = 2对应的pm

            XmlDocument doc = new XmlDocument();
            doc.LoadXml(xml);

string xpath = "//row[@id=2]/name";

XmlNode node = doc.SelectSingleNode(xpath);

            if (node != null)
            {
                if (node.Attributes["pm"] != null)
                    MessageBox.Show(node.Attributes["pm"].Value.ToString());
                else
                    MessageBox.Show("未找到PM属性。");
            }
        }