C++: Pure Virtual Function Called

最近从水木C++版看到了这个问题，什么情况下纯虚函数会被调用？

这个链接解释的比较清楚，http://www.artima.com/cppsource/pure_virtual.html

下面是一个demo，在基类构造函数中调用纯虚函数，

>> cat pure1.C  #include <iostream>using namespace std;class B {public:        B()        {                func();        }        void virtual func() = 0;};class D : public B {public:        void func() {                cout << " I am in D " << endl;        }};int main(){        D *pd = new D();}

Solaris Sun CC,

>> CC pure1.C   "pure1.C", line 8: Warning: Attempt to call a pure virtual function B::func() will always fail.1 Warning(s) detected.>> ./a.outPure virtual function calledAbort(coredump)

Linux g++

>> g++ pure1.C      pure1.C: In constructor `B::B()':pure1.C:8: error: abstract virtual `virtual void B::func()' called from constructor

在基类构造函数中间接调用纯虚函数，

>> cat pure.C#include <iostream>using namespace std;class B {public:        B()        {                fun();        }        void fun()        {                func();        }        void virtual func() = 0;};class D : public B {public:        void func() {                cout << " I am in D " << endl;        }};int main(){        D *pd = new D();}

Linux g++,

>> g++ pure.C>> ./a.out pure virtual method calledterminate called without an active exceptionAbort(coredump)

Solaris Sun CC,

>> CC pure.C    >> ./a.outPure virtual function calledAbort(coredump)