Android  Http请求

来源:互联网 发布:增值税发票软件app 编辑:程序博客网 时间:2024/06/04 20:00
package jftt.test;import java.io.IOException;import java.util.List;import org.apache.http.HttpResponse;import org.apache.http.HttpStatus;import org.apache.http.NameValuePair;import org.apache.http.client.ClientProtocolException;import org.apache.http.client.HttpClient;import org.apache.http.client.entity.UrlEncodedFormEntity;import org.apache.http.client.methods.HttpGet;import org.apache.http.client.methods.HttpPost;import org.apache.http.impl.client.DefaultHttpClient;import org.apache.http.params.BasicHttpParams;import org.apache.http.params.HttpConnectionParams;import org.apache.http.params.HttpParams;import android.util.Log;public class HttpRequest {/** *Post请求 */public void doPost(String url , List<NameValuePair> nameValuePairs){//新建HttpClient对象  HttpClient httpclient = new DefaultHttpClient();//创建POST连接HttpPost httppost = new HttpPost(url);try {////使用PSOT方式,必须用NameValuePair数组传递参数//List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();//nameValuePairs.add(new BasicNameValuePair("id", "12345"));//nameValuePairs.add(new BasicNameValuePair("stringdata","hps is Cool!"));httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));HttpResponse response = httpclient.execute(httppost);} catch (ClientProtocolException e) {e.printStackTrace();} catch (IOException e) {e.printStackTrace();}}/** *Get请求 */public void doGet(String url){HttpParams httpParams = new BasicHttpParams();    HttpConnectionParams.setConnectionTimeout(httpParams,30000);      HttpConnectionParams.setSoTimeout(httpParams, 30000);              HttpClient httpClient = new DefaultHttpClient(httpParams);  // GET    HttpGet httpGet = new HttpGet(url);try {HttpResponse response = httpClient.execute(httpGet);if (response.getStatusLine().getStatusCode() != HttpStatus.SC_OK){Log.i("GET", "Bad Request!");}} catch (IOException e) {e.printStackTrace();}}}

需要主要的是:

1.   使用POST方式时,传递参数必须使用NameValuePair数组

2.   使用GET方式时,通过URL传递参数,注意写法

3.      通过setEntity方法来发送HTTP请求

4.      通过DefaultHttpClientexecute方法来获取HttpResponse

5. 通过getEntity()从Response中获取内容

String content = EntityUtils.toString(response.getEntity());

特别说明:

对于WCF的json服务,请求时如下:

  
    /**      *Post请求      * @throws IOException      * @throws ClientProtocolException      */      public static String doPost(String url , List<NameValuePair> nameValuePairs) throws ClientProtocolException, IOException{     String result = null;        //新建HttpClient对象            HttpClient httpclient = new DefaultHttpClient();          //创建POST连接          HttpPost httppost = new HttpPost(url);          httppost.setHeader("content-type", "application/json");        try {        if(nameValuePairs != null) {StringEntity entity = new StringEntity("这里是JSON数据,如{"id":"12","name":"xiaoming"}", "utf-8");entity.setContentType("application/json");entity.setContentEncoding("utf-8");httppost.setEntity(entity);        }          //        if(nameValuePairs != null) {//        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs, HTTP.UTF_8));  //        }            HttpResponse response = httpclient.execute(httppost);              if (response.getStatusLine().getStatusCode() != 404)            {                    result = EntityUtils.toString(response.getEntity());                    Logger.d(TAG, "Response: " + result);            }        } finally {                }        return result;    }