USACO 3.2.4 Feed Ratios
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题目既然告诉我们答案的三个数都会小于100
那么就别客气了,直接暴力。
/*PROG:ratiosLANG:C++*/#include <cstdio>using namespace std;int x[4], y[4], z[4], X, Y, Z, R, I, J, K, ans = ~0U>>1;int main(){ freopen("ratios.in", "r", stdin); freopen("ratios.out", "w", stdout); for (int i = 0;i < 4;++i) scanf("%d%d%d", &x[i], &y[i], &z[i]); for (int i = 0;i < 100;++i) for (int j = 0;j < 100;++j) for (int k = 0;k < 100;++k) { X = Y = Z = 0; X += x[1]*i, Y += y[1]*i, Z += z[1]*i; X += x[2]*j, Y += y[2]*j, Z += z[2]*j; X += x[3]*k, Y += y[3]*k, Z += z[3]*k; if (!X) continue; if (X % x[0] != 0) continue; int tmp = X / x[0]; if (y[0] * tmp != Y) continue; if (z[0] * tmp != Z) continue; if (i+j+k < ans) { ans = i+j+k; I = i, J = j, K = k, R = tmp; } } if (I || J || K) printf("%d %d %d %d\n", I, J, K, R); else printf("NONE\n");}
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