boost学习之-生产者消费者问题例子

生产者消费者问题在线程编程中是基础问题，很重要，很多其他问题的解决都通过扩展该问题的解决方法来解决的；

boost中的一个例子是这样写的，很简洁；所以boost很强大，屏蔽掉了很多繁琐的问题；

#include <boost/thread/condition.hpp>
#include <boost/thread/mutex.hpp>
#include <boost/thread/thread.hpp>
#include <iostream>
#include <vector>

class bounded_buffer : private boost::noncopyable
{
public:
    typedef boost::mutex::scoped_lock lock;
    bounded_buffer(int n) : begin(0), end(0), buffered(0), circular_buf(n) { }
    void send (int m) {
        lock lk(monitor);
        while (buffered == circular_buf.size())
            buffer_not_full.wait(lk);
        circular_buf[end] = m;
        end = (end+1) % circular_buf.size();
        ++buffered;
        buffer_not_empty.notify_one();
    }
    int receive() {
        lock lk(monitor);
        while (buffered == 0)
            buffer_not_empty.wait(lk);
        int i = circular_buf[begin];
        begin = (begin+1) % circular_buf.size();
        --buffered;
        buffer_not_full.notify_one();
        return i;
    }
private:
    int begin, end, buffered;
    std::vector<int> circular_buf;
    boost::condition buffer_not_full, buffer_not_empty;
    boost::mutex monitor;
};
bounded_buffer buf(2);

void sender() {
    int n = 0;
    while (n < 100) {
        buf.send(n);
        std::cout << "sent: " << n << std::endl;
        ++n;
    }
    buf.send(-1);
}

void receiver() {
    int n;
    do {
        n = buf.receive();
        std::cout << "received: " << n << std::endl;
    } while (n != -1); // -1 indicates end of buffer
}

int main()
{
    boost::thread thrd1(&sender);
    boost::thread thrd2(&receiver);
    thrd1.join();
    thrd2.join();
}

读例子是很好的学习方式！