1196. History Exam

1196. History Exam

Time Limit: 2.0 second
Memory Limit: 16 MB

Professor of history decided to simplify the examination process. At the exam, every student should write a list of historic dates she knows (she should write the years only and, of course, must be able to explain what event took place in this or that year). Professor has a list of dates that students must know. In order to decide upon the student's mark, Professor counts the number of dates in the student's list that are also present in his list. The student gets her mark according to the number of coincidences.

Your task is to automatize this process. Write a program that would count the number of dates in the student's list that also occur in Professor's list.

Input

The first line contains the number N of dates in Professor's list, 1 ≤ N ≤ 15000. The followingN lines contain this list, one number per line. Each date is a positive integer not exceeding 10⁹. Professor's list is sorted in non-descending order. The following line contains the number Mof dates in the student's list, 1 ≤ M ≤ 10⁶. Then there is the list itself; it is unsorted. The dates here satisfy the same restriction. Both in Professor's and in the student's lists dates can appear more than once.

Output

Output the number of dates in the student's that are also contained in Professor's list.

Sample

inputoutput

21054149241492655361492100

2

我不知道为什么之前不用二分的时候，明明结果正确，也报错。。（Wrong answer，，无关时间问题）

#include <iostream>using namespace std;int a[15000], b[1000000];int main(){int n, m, i, j, num = 0, l, r, k;cin>>n;for (i=0; i<n; i++)cin>>a[i];cin>>m;for (i=0; i<m; i++)cin>>b[i];for (i=0; i<m; i++){l = 0;r = n - 1;while (l <= r){k = (l + r) / 2;if (b[i] == a[k]){num++;break;}else if (b[i] < a[k])r = k - 1;elsel = k + 1;}}cout<<num<<endl;}