给出一个函数来输出一个字符串的所有排列

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#include <stdio.h>void permutation(char * p_str, char * p_begin){    if(!p_str || !p_begin)    {        return;    }     /* * If p_begin points to the end of string, * this round of permutation is finished, * print the permuted string. */    if('\0' == *p_begin)    {        printf("%s\n", p_str);    }    /* Otherwise, permute string. */    else    {        char * p_ch;          for(p_ch = p_begin; *p_ch != '\0'; ++p_ch)        {            char temp;               /* Swap p_ch and p_begin. */            temp = *p_ch;            *p_ch = *p_begin;            *p_begin = temp;               permutation(p_str, p_begin + 1);               /* Restore p_ch and p_begin. */            temp = *p_ch;            *p_ch = *p_begin;            *p_begin = temp;        }    }}int main(int argc, char * argv[]){            char strr[4]="123";    char strd[4]; permutation(strr, strr);    return 0;}