种类为两种时，并查集的解题应用poj1703和hdu1829

将两种的种类并查集转化为普通并查集

例题：poj 1703 和 hdu 1829

当有N各节点且他们之间只有两种关系时，可以再虚拟出N个节点，对这2*N个节点进行操作即可

//hdu1829import java.io.BufferedReader;import java.io.IOException;import java.io.InputStreamReader;import java.io.OutputStreamWriter;import java.io.PrintWriter;import java.io.StreamTokenizer;public class hdu1829ABugsLife {static int max=6010;static int parent[]=new int[max];static StreamTokenizer in = new StreamTokenizer(new BufferedReader(new InputStreamReader(System.in)));static  PrintWriter out = new PrintWriter(new OutputStreamWriter(System.out));final static  int nextInt() throws IOException {in.nextToken();return (int) in.nval;}static void init(){for(int i=0;i<max;i++)parent[i]=i;}static int find(int x){if(x!=parent[x])parent[x]=find(parent[x]);return parent[x];}static void union(int a,int b){int fa=find(a);int fb=find(b);if(fa==fb)return;parent[fa]=fb;}public static void main(String[] args) throws IOException {int num=nextInt();for(int i=1;i<=num;i++){init();int n=nextInt();int m=nextInt();int data1[]=new int[m+1];int data2[]=new int[m+1];for(int j=1;j<=m;j++){data1[j]=nextInt();data2[j]=nextInt();}boolean mark=true;for(int j=1;j<=m;j++){int a=data1[j];int b=data2[j];int fa=find(a);int fb=find(b);//System.out.println("fa :"+fa+"fb :"+fb);if(fa==fb){System.out.println("Scenario #"+i+":");System.out.println("Suspicious bugs found!");mark=false;//System.out.println(mark);break;}else{union(a,b+n);union(b,a+n);//union(a,b);}}if(mark){System.out.println("Scenario #"+i+":");System.out.println("No suspicious bugs found!");}System.out.println();}}}
//poj1703
/*将n个人的看作是有2*n个，若a与b不在同一个集合时，就将a与（b+n）合并，b与（a+n）合并 * 这样就转化为了普通并查集 */import java.io.BufferedReader;import java.io.IOException;import java.io.InputStreamReader;import java.io.OutputStreamWriter;import java.io.PrintWriter;import java.io.StreamTokenizer;public class poj1703T {static StreamTokenizer in = new StreamTokenizer(new BufferedReader(new InputStreamReader(System.in)));static  PrintWriter out = new PrintWriter(new OutputStreamWriter(System.out));final static  int nextInt() throws IOException {in.nextToken();return (int) in.nval;}static String next() throws IOException {in.nextToken();return (String)in.sval;}static int max=300010;static int parent[]=new int[max];static void init(){for(int i=0;i<max;i++)parent[i]=i;}static int find(int x){if(x!=parent[x]){parent[x]=find(parent[x]);}return parent[x];}static void union(int a,int b){int fa=find(a);int fb=find(b);if(fa==fb)return;parent[fa]=fb;}public static void main(String[] args) throws IOException {//Scanner in=new Scanner(System.in);int num=nextInt();while(num--!=0){init();int n=nextInt();int m=nextInt();for(int i=1;i<=m;i++){String inc=next();int a=nextInt();int b=nextInt();if(inc.equals("D")){union(a,b+n);union(b,a+n);}else {if(find(a)==find(b))System.out.println("In the same gang.");else if(find(a)==find(b+n)||find(b)==find(a+n)){System.out.println("In different gangs.");}else{System.out.println("Not sure yet.");}}}}}}