C++的int初始化

int MyInt(56);

std::cout<<"MyInt="<<MyInt<<std::endl;

int MySecondInt = int();        //int变量可以这样初始化

std::cout<<MySecondInt<<std::endl;

        //那么可不可以这样初始化呢? 

int MyThirdInt(int());    //error!!! now, this is exactly a function

        

所以 MyThirdInt 正确的写法是

int MyThirdInt(int())

{

        // other code...  

return 0;

}

既然MyThirdInt 是一个函数, 那么里面的参数是什么东东呢?

//我们在声明一个函数

int OtherInt()

{

return 33;

}

//再看三行代码

int (*pfunc)();

pfunc = OtherInt;

std::cout<<"MyThirdInt is: "<<MyThirdInt(pfunc)<<std::endl;

MyThirdInt 的参数是个函数指针,但是函数指针好像不能取出来....

所以这个特殊的Int变量需要重新定义,就像下面这样:

int MyThirdInt(int (*pInt)())

{

return pInt();

}

======================完整代码========================

// hellomsg.cpp : 

//

#include "stdafx.h"

#include <iostream>

int OtherInt()

{

return 33;

}

int MyThirdInt(int (*pInt)())

{

return pInt();

}

int _tmain(int argc, _TCHAR* argv[])

{

int MyInt(56);

std::cout<<"MyInt="<<MyInt<<std::endl;

int MySecondInt = int();

std::cout<<MySecondInt<<std::endl;

int (*pfunc)();

pfunc = OtherInt;

std::cout<<"MyThirdInt is: "<<MyThirdInt(pfunc)<<std::endl;

return 0;

}