Hi,
i had installed ACE5.5 OS windows 2000 c++ build 6.0
lib: ACE_bd.lib
I am reading "
ACE Programmer's Guide, The: Practical Design Patterns for Network and
Systems Programming"
the code
Let's take a look at a simple application:
#include "ace/Log_Msg.h"
void foo (void);
int ACE_TMAIN (int, ACE_TCHAR *[])
{
ACE_TRACE(ACE_TEXT ("main"));
ACE_DEBUG ((LM_INFO, ACE_TEXT ("%IHi Mom/n")));
foo();
ACE_DEBUG ((LM_INFO, ACE_TEXT ("%IGoodnight/n")));
return 0;
}
void foo (void)
{
ACE_TRACE (ACE_TEXT ("foo"));
ACE_DEBUG ((LM_INFO, ACE_TEXT ("%IHowdy Pardner/n")));
}
If you compile and execute the preceding code, you should get something
like this:
(1024) calling main in file `Simple1.cpp' on line 7
Hi Mom
(1024) calling foo in file `Simple1.cpp' on line 18
Howdy Pardner
(1024) leaving foo
Goodnight
(1024) leaving main
:( but what i get is
Hi Mom
Howdy Pardner
Goodnight
The compile-time values of three configuration settings control whether
the logging macros produce logging method calls: ACE_NTRACE,
ACE_NDEBUG, and ACE_NLOGGING.
so i change it
my code is
#include "ace/Log_Msg.h"
#define ACE_NTRACE 0
#define ACE_NDEBUG 0
#define ACE_NLOGGING 0
I think you need to set this stuff *before* you #include any ACE
files... Please see
ACE_ROOT/examples/Misc/test_trace.cpp
for an example of how to do it right.
thanks,
Doug
void foo (void);
int ACE_TMAIN (int, ACE_TCHAR *[])
{
ACE_TRACE(ACE_TEXT ("main"));
ACE_DEBUG ((LM_INFO, ACE_TEXT ("%IHi Mom/n")));
foo();
ACE_DEBUG ((LM_INFO, ACE_TEXT ("%IGoodnight/n")));
system("Pause");
return 0;
}
void foo (void)
{
ACE_TRACE (ACE_TEXT ("foo"));
ACE_DEBUG ((LM_INFO, ACE_TEXT ("%IHowdy Pardner/n")));
}
i still get
Hi Mom
Howdy Pardner
Goodnight
what 's wrong with my code? thank you
benjiam
------------------------------------------------------------------------------------------------------------------------------
照着Doug回复的方法，在#include 之前加了一条#define ACE_NTRACE 0 ，问题解决了 。在《指南》中也这样说到，ACE_TRACE的值默认为1（禁用），它被解释为“不”。因此，要使ACE_TRACE产生日志方法调用，把它设为0就可以了。
