The Center of Gravity(一道很很简单的几何题)
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The Center of Gravity
Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 2994 Accepted Submission(s): 1668
原题链接:点击打开链接
Total Submission(s): 2994 Accepted Submission(s): 1668
原题链接:点击打开链接
Problem Description
Everyone know the story that how Newton discovered the Universal Gravitation. One day, Newton walked
leisurely, suddenly, an apple hit his head. Then Newton discovered the Universal Gravitation.From then
on,people have sovled many problems by the the theory of the Universal Gravitation. What's more, wo also
have known every object has its Center of Gravity.
Now,you have been given the coordinates of three points of a triangle. Can you calculate the center
of gravity of the triangle?
leisurely, suddenly, an apple hit his head. Then Newton discovered the Universal Gravitation.From then
on,people have sovled many problems by the the theory of the Universal Gravitation. What's more, wo also
have known every object has its Center of Gravity.
Now,you have been given the coordinates of three points of a triangle. Can you calculate the center
of gravity of the triangle?
Input
The first line is an integer n,which is the number of test cases.
Then n lines follow. Each line has 6 numbers x1,y1,x2,y2,x3,y3,which are the coordinates of three points.
The input is terminated by n = 0.
Then n lines follow. Each line has 6 numbers x1,y1,x2,y2,x3,y3,which are the coordinates of three points.
The input is terminated by n = 0.
Output
For each case, print the coordinate, accurate up to 1 decimal places.
Sample Input
21.0 2.0 3.0 4.0 5.0 2.01.0 1.0 4.0 1.0 1.0 5.00
Sample Output
3.0 2.72.0 2.3
Source
HDU 2007-6 Programming Contest
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xhd
AC CODE:
#include <iostream>#include <cstdio>using namespace std;int main(){ double x[3], y[3]; int T; while(cin >> T && T) { while(T--) { for(int i = 0; i < 3; i++) cin >> x[i] >> y[i]; x[0] += x[1] + x[2]; y[0] += y[1] + y[2]; printf("%.1lf %.1lf\n", x[0] / 3.0, y[0] / 3.0); } } return 0;}
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