关于configure中的build/host/target

可以参考:http://www.airs.com/ian/configure/configure_toc.html
Reference:
http://www.tcpdump.org/lists/workers/2001/11/msg00148.html

Nope. See `info standards' for the definition of $build*, $host* and
$target* macros.
 Basically, $build* refer to the system compilation is being performed on,
$host* refer to the system compiled binaries are to run on
 $target* refer to the system compiled binaries will handle. As
such $target* usually have a meaning for developemt tool only.

So far packages that make use of $target* I know of are binutils, gcc,
gdb and ksymoops (a Linux run-time error disassembler). Let's take
binutils as an example. I compile it in several ways, following are
examples of configure invocations:

 

1. `./configure --build=mipsel-linux --host=mipsel-linux
--target=mipsel-linux' will build native mipsel-linux binutils on
mipsel-linux.

 

2. `./  可以参考:http://www.airs.com/ian/configure/configure_toc.html
Reference:
http://www.tcpdump.org/lists/workers/2001/11/msg00148.html--build=i386-linux --host=mipsel-linux
--target=mipsel-linux' will cross-build native mipsel-linux binutils on
i386-linux.

 

3. `./configure --build=i386-linux --host=i386-linux
--target=mipsel-linux' will build mipsel-linux cross-binutils on
i386-linux.

 

4. `./configure --build=mipsel-linux --host=i386-linux
--target=mipsel-linux' will cross-build mipsel-linux cross-binutils for
i386-linux on mipsel-linux.

As you see, only if $build != $host a cross-compilation is performed.

 

   具体解释一下,build就是你正在使用的机器,
                         host就是你编译好的程序可以运行的平台,
                         target就是你编译的程序可以处理的平台.一般来说,我们平时所说的交差编译用不到他target的,比 如./configure --build=i386-linux,--host=arm-linux就可以了,在386的平台上编译可以运行在arm板的程序.但是,一般我们都是 编译程序,而不是编译工具,如果我们编译工具,比如gcc,这个target就有用了.如果我们需要在一个我们的机器上为arm开发板编译一个可以处理 mips程序的gcc,那么target就是mips了