用递归实现查找字符串中相同字符连续出现次数的最大值

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http://blog.csdn.net/arduousbonze/article/details/4293626

// recursive.cpp : Defines the entry point for the console application.//#include "stdafx.h"#include <iostream>using namespace std;//char szGame[]={'w','w','k','k','k','k','l','l','l','m','m','m'};char szGame[]={'w','w','k','l','l','l','m','m','m'};int countLongest(char* pBuf);int main(int argc, char* argv[]){cout<<countLongest(szGame)<<endl;return 0;}int max=0;int countLongest(char* pBuf){/*int result=0;char *p=pBuf;if((*pBuf)=='/0'){result>max?result:max;cout<<"max="<<max<<endl;return result;}while((*pBuf)!='/0'&&(*p)==(*pBuf)){result++;pBuf++;}result>max?(max=result):max;p++;return countLongest(p);*///improved versionint result=0;char *p=pBuf;if((*pBuf)=='/0'){return result;}while((*pBuf)!='/0'&&(*p)==(*pBuf)){result++;pBuf++;}p++;return result>countLongest(p)?result:countLongest(p);}


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