#include <stdio.h>#include <conio.h>/*1、编程解决如下问题：鸡翁一，值钱五；鸡母一，值钱三；鸡雏三，值钱一。 百钱买百鸡,问鸡翁，鸡母，鸡雏各几何？（20分）*/int main(){ int rooster = 0,//公鸡 hen = 0, //母鸡 child = 0; //鸡雏 for (rooster = 0; rooster <= 20; rooster++) { for (rooster = 0; hen <= 33; hen++) { child = 100 - rooster - hen; if (child >= 0 && 100 == (rooster * 5 + hen * 3 + child / 3 * 1)) { printf("鸡翁: %d\t鸡母: %d\t鸡雏: %d\n", rooster, hen, child); } } } getch(); return 0;} int i; for (i = 0; i < size; i++) { if (strcmp(tmp, art[i].word) == 0) return i;//返回下标 } return -1;}/*2、编程实现：有二维数组a[3][3]={{1.3,2.7,3.6},{2,3,4.7},{3,4,1.27}}，将数组a的每一行元素均除以该行上绝对值最大的元素,按行输出新数组。（20分）*/#include <stdio.h>#include <conio.h>int main(){ float a[3][3] = {{1.3, 2.7, 3.6}, {2, 3, 4.7}, {3, 4, 1.27}}, max; int i, j; puts("处理前："); for (i = 0; i < 3; i++) { for (j = 0; j < 3; j++) { printf("%6f ", a[i][j]); } putchar(10); } for (i = 0; i < 3; i++) { max = fabs(a[i][i]); for (j = 1; j < 3; j++) { if (max < fabs(a[i][j])) max = a[i][j]; } for (j = 0; j < 3; j ++) a[i][j] /= max; } puts("处理后："); for (i = 0; i < 3; i++) { for (j = 0; j < 3; j++) { printf("%6f ", a[i][j]); } putchar(10); } return 0;}/*3、编程：设x、y取值为区间[1,10]的整数， f(x,y)=(3x-2y)/(x+y)，求使f(x,y)取最小值的x1、y1，要求使用自定义函数实现f（x,y）功能。（20分）*/#include <stdio.h>#include <conio.h>double getFx(int x, int y){ return (3 * x - 2 * y) / (x + y);}int main(){ double fx = 100000, tmp = 0; int x, y; int minx, miny; for (x = 1, y = 1; x <= 10 && y <= 10; x++, y++) { tmp = getFx(x, y); if (fx - tmp > 1e-7) { fx = tmp; minx = x; miny = y; } } printf("%d %d\n", minx, miny); return 0;}/*4、编写函数fun，其功能是：在字符串中所有数字字符前加一个“*”字符，要求通过指针实现。（20分）*/#include <stdio.h>#include <conio.h>#include <string.h>int main(){ char str[200], *pBegin = str; printf("输入一个串:\n"); gets(pBegin); for (; *pBegin != '\0'; pBegin++) { if (*pBegin >= '1' && *pBegin <= '9') { putchar('*'); putchar(*pBegin); } else putchar(*pBegin); } putchar(10); getch(); return 0;}/*5、编程：已知学生记录由学号和学习成绩构成，N名学生的记录已存入结构体数组中，找出成绩最低的学生，并输出这个学生的信息，已知学生信息如下。（20分）A01，81；A02，89；A03，66；A04，87；A05，77A06，90；A07，79；A08，61；A09，80；A10，71*/#include <stdio.h>#include <conio.h>#include <string.h>typedef struct{ char sno[5]; int score;}Student;int main(){ Student stu[10] = {{"A01", 81}, {"A02", 89}, {"A03", 66}, {"A04", 87}, {"A05", 77}, {"A06", 90}, {"A07", 79}, {"A08", 61}, {"A09", 80}, {"A10", 71}}; int i, min = stu[0].score, index; for (i = 1; i < 10; i++) { if (min > stu[i].score); { min = stu[i].score; index = i; } } printf("成绩最低的学生的信息:\n"); printf("%-5s %d\n", stu[index].sno, min); getch(); return 0;}/*5、编程：已知学生记录由学号和学习成绩构成，N名学生的记录已存入结构体数组中，找出成绩最低的学生，并输出这个学生的信息，已知学生信息如下。（20分）A01，81；A02，89；A03，66；A04，87；A05，77A06，90；A07，79；A08，61；A09，80；A10，71*/#include <stdio.h>#include <conio.h>#include <string.h>typedef struct{ char sno[5]; int score;}Student;int main(){ Student stu[10] = {{"A01", 81}, {"A02", 89}, {"A03", 66}, {"A04", 87}, {"A05", 77}, {"A06", 90}, {"A07", 79}, {"A08", 61}, {"A09", 80}, {"A10", 71}}; int i, min = stu[0].score, index; for (i = 0; i < 10; i++) { if (min > stu[i].score) { min = stu[i].score; index = i; } } printf("成绩最低的学生的信息:\n"); printf("%-5s %d\n", stu[index].sno, stu[index].score); getch(); return 0;}/*6、附加题：编写一个函数InverseByWord(char *sentence)，实现一个英文句子按单词逆序存放的功能,并给出测试程序。（50分）如：This is an interesting programme.逆序后变为：.programme interesting an is This*/#include <stdio.h>#include <conio.h>#include <string.h>void InverseByWord(char *sentence){ int i, j = strlen(sentence) - 1, wordLen = 0; int index = 0, len = j + 1; char tmp[201]; if (sentence[j] == '.') { tmp[index++] = '.'; j--; } while (j >= 0) { wordLen = 0; while (sentence[j] != ' ') { j --; wordLen ++; } for (i = 0; i < wordLen; i++) { if (j >= 0) tmp[index++] = sentence[j + i + 1]; } while (sentence[j] == ' ')//去掉空格 { tmp[index++] = sentence[j--]; } } strncpy(sentence, tmp, len);}int main(){ char str[201]; int i = 0; str[0] = ' '; printf("输入一个字符串:\n"); gets(str+1); InverseByWord(str); printf("逆序后：\n"); puts(str); getch(); return 0;}
